我正在将一些表单数据解析为 Ajax 并希望触发一段 php 代码。
所以在代码中,我目前在提交时提醒电子邮件地址,我想将其解析为newsletter_signup函数并在最底部运行 php 代码块,表单中的电子邮件地址进入 php.ini 文件。
我怎样才能做到这一点?
<form action="/event" method="POST" id="signupForm">
<input type="hidden" name="event" value="mc_newsletter_add">
<input type="hidden" name="data[source]" value="newsletter">
<input checked=checked type="checkbox" name="data[newsletter_onetime]" id="newsletter_onetime" class="newsletter-optins">
<input checked=checked type="checkbox" name="data[promos]" id="promos" class="newsletter-optins">
<input class="modal-newsletter-input" id="EmailAddress" name="data[customers_email_address]" placeholder="Enter your email here" required="required" type="email" value="<?php if(isset($_GET['email'])){echo $_GET['email'];}?>" aria-required="true">
<input class="modal-newsletter-signup" id="newslettersignup" name="Submit" type="submit" value="Yes, sign me up" />
</form>
<script>
$("#signupForm").submit(function(e) {
e.preventDefault();
var form = $(this);
var email = $("#EmailAddress").val();
$.ajax({
type: "POST",
url: form.attr('action'),
data: form.serialize(),
success: function(data)
{
console.log(data); //data contain response from your php script
register_signup();
newsletter_signup(email);
form.replaceWith("<br /><p>Thanks for signing up!</p>");
}
});
});
function register_signup(){
ga( 'send', 'event', 'Newsletter Sign Up', 'submit' );
}
function newsletter_signup(email){
$('#signupForm').load(
"newsletter-call.php",
{
'key1': email,
}
);
}
</script>
子衿沉夜