Java：可以调用具有未知参数的函数

Question

从理论上讲，如果类“sensorFinal”无法访问整数“value”，“sensorFinal”类中的函数“absSensor”如何能够调用“proximitySensor”类中的函数“proximitySensorAdjusted”？

是否有一种标准方法可以调用对数据访问受限的函数，或者是否有解决方法？提前致谢！

public class proximitySensor

{

    double adjustment = 5;

    public double proximitySensorAdjusted(int value)

    {

        double finalValue = value + adjustment;

        return finalValue; 

    }

}

public class sensorFinal

{

    public double absSensor()

    {

        proximitySensor sensorValue = new proximitySensor();

        sensorValue.proximitySensorAdjusted( ??? ) 

    }

}

Answer 1

您可以使用方法重载。public double proximitySensorAdjusted(int value) {    double finalValue;    if(value == -1) {        finalValue = adjustment;    } else {        finalValue = value + adjustment;    }    return finalValue;}public double proximitySensorAdjusted() {    return proximitySensorAdjusted(-1); //call with some default value}现在您可以调用sensorValue.proximitySensorAdjusted();.

Answer 2

而不是???您需要指定任何整数值，例如0or 5。在您的示例中int value是一个参数名称。只有该函数内的代码才能访问它。

Answer 3

您可以使用选项，这与简单地重载您的函数没有什么不同，正如这里建议的另一个答案。public class proximitySensor {&nbsp; &nbsp; double adjustment = 5;&nbsp; &nbsp; public double proximitySensorAdjusted(Optional<Integer> value) {&nbsp; &nbsp; &nbsp; &nbsp; double finalValue = value.map(v -> v + adjustment)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;.orElseGet(() -> {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ... // Do something intelligent here&nbsp; &nbsp; &nbsp; &nbsp; });&nbsp; &nbsp; &nbsp; &nbsp; return finalValue;&nbsp;&nbsp; &nbsp; }}现在您使用以下命令调用该函数：sensorValue.proximitySensorAdjusted(Optional.empty());作为旁注，Java 中类名的命名约定是Capitalized，因此您的proximitySensor类应该被称为ProximitySensor。