在阅读实际行之前，我将如何自动解析我打开的 audit.log 文件的语法？

Question

我正在尝试自动解析最初在 Python 程序中打开的日志文件，以便在我开始从文件本身读取实际行之前，其输出采用人类可读的格式。我该怎么做？

with open('/var/log/audit/audit.log') as audit_raw:

    audit_formatted=subprocess.call(["ausearch", "-i", audit_raw])

    line = audit_formatted.readline()

当我尝试这样做时的错误消息：

Traceback (most recent call last):

  File "./email_script.py", line 29, in <module>

    audit_log=subprocess.call(["ausearch", "-i", audit_raw])

  File "/usr/lib/python3.6/subprocess.py", line 267, in call

    with Popen(*popenargs, **kwargs) as p:

  File "/usr/lib/python3.6/subprocess.py", line 709, in __init__

    restore_signals, start_new_session)

  File "/usr/lib/python3.6/subprocess.py", line 1275, in _execute_child

    restore_signals, start_new_session, preexec_fn)

TypeError: expected str, bytes or os.PathLike object, not _io.TextIOWrapper

Answer 1

您使用正确的参数调用ausearch并解析其输出。在这里被盗：用于处理 linux 的 audit.log 的 Python 库？（这是一个要求图书馆认可的题外问题）并且可能会从 SO 中消失 - 这就是我决定反对“重复”的原因。方尖碑回答：import subprocessdef read_audit(before,now,user):&nbsp; &nbsp; auparam = " -sc EXECVE"&nbsp; &nbsp; cmd = "ausearch -ts " + before.strftime('%H:%M:%S') + " -te " + now.strftime('%H:%M:%S') + " -ua " + user + auparam&nbsp; &nbsp; p = subprocess.Popen(cmd, shell=True, stdout=subprocess.PIPE)&nbsp; &nbsp; res = p.stdout.read().decode()&nbsp; &nbsp; return res