Java - 遇到空格进行 ASCII 转换时 Printf 损坏

Question

我有一个脚本，它应该采用一个由数字和字母组成的字符串，并将它们分解为ASCII/Hex相应列下的值。它可以完美运行，直到我在字符串中的任何位置放置一个空格。它将正常打印所有内容直到空格，然后中断没有错误。

Ex. (works):

kdillon76

Ex. (does NOT work):

kdillon 76

在我的 For 循环中，我有一个 If 语句，说明如果字符是数字，则“执行此操作”，然后是一个 Else 语句以涵盖任何“其他”内容。Else 语句不应该能够将空格转换为“32”ASCII 数字吗？

非常感谢任何和所有帮助！

  import java.util.*; // Load all Utility Classes

public class DKUnit3Ch12 { // Begin Class DKUnit3Ch12

    public static void main(String[] args) { // Begin Main

        Scanner myScan = new Scanner(System.in); // Initialize the Scanner

        String myInput; // Define a new Variable

        System.out.print("Please enter a string of any length: "); //Print the text

        myInput = myScan.next(); // Define a new Variable with the next user input

        System.out.printf("%n%-8s%-16s%-16s%s%n", "Initial", "ASCII(char)", "ASCII(int)", "Hex"); // Print the labels with proper tablature

        for(int x = 0; x < myInput.length(); x++) { // Begin For Loop

            char myChar = myInput.charAt(x); // Define a new Variable based on position in index

            if(Character.isDigit(myChar)) { // Begin If Statement (if the character is a digit)

                System.out.printf("%-24s%-16d%02X%n", myChar, (int)myChar, (int)myChar); // Print the items with proper tablature including capitalized Hex

            } // End If Statement

            else { // Begin Else Statement (if the character is NOT a digit)

                System.out.printf("%-8s%-32d%02X%n", myChar, (int)myChar, (int)myChar);  // Print the items with proper tablature including capitalized Hex

            } // End Else Statement

        } // End For Loop

        System.out.print("\nThank you for playing!"); // Print the text

        myScan.close(); // Close the Scanner

    } // End Main

} // End Class DKUnit3Ch12

Answer 1

从文档：A Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace.

Answer 2

替换myScan.next()为myScan.nextLine()