Python 读取 XAML 文件中的所有元素并替换一些值
所以我有XML文件，在文件里面我有很多elements这样的：
<name search = "read TTT: write">
<version id = "1.0.0">
<value>myVal</value>
<method>myMethod</method>
</version>
</name>
因此，在每一个元素我需要找到这search = "read TTT: write"行，在此情况下，read TTT: write开始与read我需要改变它（用一个字符串替换读）。
最好的\最快的方法是什么？
更新
因此，如果我有element这样的情况（存在“阅读”一词）：
<name search = "read TTT: write">
<version id = "1.0.0">
<value>myVal</value>
<method>myMethod</method>
</version>
</name>
我想用这个替换它（我只替换读取）：
<name search = "NewValue TTT: write">
<version id = "1.0.0">
<value>myVal</value>
<method>myMethod</method>
</version>
</name>
幕布斯7119047浏览 393回答 3
3回答
-
杨魅力
使用minidom：from xml.dom import minidomxmldoc = minidom.parseString(xml)tags = xmldoc.getElementsByTagName("name")firstchild = tags[0]firstchild.attributes["search"].value = 'NewValue TTT: write'print(xmldoc.toxml())输出：<?xml version="1.0" ?><name search="NewValue TTT: write"> <version id="1.0.0"> <value>myVal</value> <method>myMethod</method> </version></name>编辑：对于多个标签，只需循环：xml = '''\<root><name search = "read TTT: write"> <version id = "1.0.0"> <value>myVal</value> <method>myMethod</method> </version></name><name search = "read2 TTT: write"> <version id = "2.0.0"> <value>myVal_2</value> <method>myMethod_2</method> </version></name></root>'''from xml.dom import minidomxmldoc = minidom.parseString(xml)tags = xmldoc.getElementsByTagName("name")for item in tags: item.attributes["search"].value = 'NewValue TTT: write'print(xmldoc.toxml())输出：<?xml version="1.0" ?><root><name search="NewValue TTT: write"> <version id="1.0.0"> <value>myVal</value> <method>myMethod</method> </version></name><name search="NewValue TTT: write"> <version id="2.0.0"> <value>myVal_2</value> <method>myMethod_2</method> </version></name></root>使用beautifulsoup：from bs4 import BeautifulSoupxml = '''\<root><name search = "read TTT: write"> <version id = "1.0.0"> <value>myVal</value> <method>myMethod</method> </version></name><name search = "read TTT: write"> <version id = "2.0.0"> <value>myVal_2</value> <method>myMethod_2</method> </version></name></root>'''soup = BeautifulSoup(xml , 'lxml')newVal = "NewValue"for elem in soup.find_all("name"): elem['search'] = elem['search'].replace(str(elem['search']).split(" ")[0], newVal) print(elem)输出：<name search="NewValue TTT: write"><version id="1.0.0"><value>myVal</value><method>myMethod</method></version></name><name search="NewValue TTT: write"><version id="2.0.0"><value>myVal_2</value><method>myMethod_2</method></version></name> -
慕桂英546537
from xml.dom.minidom import parse #minidom does the trickdom = parse('my_file.xml') #read in your fileres = dom.getElementsByTagName('name') #fetch the desired elements in the treefor element in res: #loop through all if element.getAttribute('search') == 'read TTT: write': #filter for the attribute and value element.setAttribute('search', 'New Value TTT: write') #in case of match, replacewith open('my_file_updated.xml','w') as f: #store the file f.write(dom.toxml()) -
万千封印
试试这个：xml = """<?xml version="1.0" encoding="UTF-8"?> <body> <name search = "read TTT: write"> <version id = "1.0.0"> <value>myVal</value> <method>myMethod</method> </version> </name> <name search = "read TTT: write"> <version id = "1.0.0"> <value>myVal</value> <method>myMethod</method> </version> </name> </body> """import xml.etree.ElementTree as ETtree = ET.fromstring(xml)sh = tree.findall('name')for name in sh: val = name.get("search") if str(val) == "read TTT: write": name.set('search', 'NewValue TTT: write')print (ET.tostring(tree))输出： <body> <name search = "NewValue TTT: write"> <version id = "1.0.0"> <value>myVal</value> <method>myMethod</method> </version> </name> <name search = "NewValue TTT: write"> <version id = "1.0.0"> <value>myVal</value> <method>myMethod</method> </version> </name> </body>
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