我找不到一种方法可以将 encryptedChar 放入字符数组,以便我可以将消息放在一行上。如果有人能给我一个简单的问题解决方案或以任何方式帮助我,那就太好了!
import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
// can get the index without key. DONE
// encrypt message. finish equation.
int encryptKey, encryptedIndex;
int plainLetterIndex = 0;
int loadingBar = 3;
char encryptedChar;
char[] alphaArray = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
String redo, message;
System.out.println("Welcome to the encrypter and decrypter program. The program will take the message");
System.out.println("and either encrypt it or decrypt it. Depending on what you choose to do.");
System.out.println("");
do {
System.out.println("Please enter your message!");
message = sc.nextLine();
message = message.toUpperCase();
System.out.print("Would you like to re-enter your message? (Y/N)");
redo = sc.nextLine();
} while (redo.equals("Y") || redo.equals("y"));
// declaring arrays
char[] messageArray = message.toCharArray();
char[] encryptedMessageArray = new char[messageArray.length];
// asking for key
System.out.println("Please input the 'key' you would like to use to encrypt your message.");
while(true){
try{
encryptKey = Integer.parseInt(sc.nextLine());
break;
} catch (NumberFormatException ignore){
System.out.println("You have entered an incorrect number, please try again!");
}
}
System.out.println(" ");
for (int i = 0; i < messageArray.length; i++) {
//System.out.println(messageArray[i]);
for (int k = 0; k < alphaArray.length; k++) {
}
}
}
sc.close();
}
}
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慕运维8079593
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