如何将嵌套的 XML 元素解组为数组？

Question

我的 XML 包含一组预定义元素，但我无法获取该数组。这是 XML 结构：

var xml_data = `<Parent>

                   <Val>Hello</Val>

                   <Children>

                      <Child><Val>Hello</Val></Child>

                      <Child><Val>Hello</Val></Child>

                      <Child><Val>Hello</Val></Child>

                   </Children>

                </Parent>`

这是完整的代码，这是操场链接。运行此命令将获取 Parent.Val，但不会获取 Parent.Children。

package main

import (

    "fmt"

    "encoding/xml"

)

func main() {

    container := Parent{}

    err := xml.Unmarshal([]byte(xml_data), &container)

    if err != nil {

        fmt.Println(err)

    } else {

        fmt.Println(container)  

    }

}

var xml_data = `<Parent>

                   <Val>Hello</Val>

                   <Children>

                      <Child><Val>Hello</Val></Child>

                      <Child><Val>Hello</Val></Child>

                      <Child><Val>Hello</Val></Child>

                   </Children>

                </Parent>`

type Parent struct {

    Val string

    Children []Child

}

type Child struct {

    Val string

}

编辑：我在这里稍微简化了这个问题。基本上我不能解组任何数组，而不仅仅是预定义的结构。以下是更新后的工作代码。在该示例中，只有一项最终出现在容器界面中。

func main() {

    container := []Child{}

    err := xml.Unmarshal([]byte(xml_data), &container)

    if err != nil {

        fmt.Println(err)

    } else {

        fmt.Println(container)  

    }

    /* 

        ONLY ONE CHILD ITEM GETS PICKED UP

    */

}

var xml_data = `

            <Child><Val>Hello</Val></Child>

            <Child><Val>Hello</Val></Child>

            <Child><Val>Hello</Val></Child>

        `

type Child struct {

    Val string

}

Answer 1

type Parent struct {&nbsp; &nbsp; Val string&nbsp; &nbsp; Children []Child&nbsp; `xml:"Children>Child"`&nbsp; //Just use the '>'}

Answer 2

对于这种嵌套，您还需要一个Children元素结构：package mainimport (&nbsp; &nbsp; "fmt"&nbsp; &nbsp; "encoding/xml")func main() {&nbsp; &nbsp; container := Parent{}&nbsp; &nbsp; err := xml.Unmarshal([]byte(xml_data), &container)&nbsp; &nbsp; if err != nil {&nbsp; &nbsp; &nbsp; &nbsp; fmt.Println(err)&nbsp; &nbsp; } else {&nbsp; &nbsp; &nbsp; &nbsp; fmt.Println(container)&nbsp;&nbsp;&nbsp; &nbsp; }}var xml_data = `<Parent>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; <Val>Hello</Val>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; <Children>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; <Child><Val>Hello</Val></Child>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; <Child><Val>Hello</Val></Child>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; <Child><Val>Hello</Val></Child>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; </Children>&nbsp; &nbsp; &nbsp; &nbsp; </Parent>`type Parent struct {&nbsp; &nbsp; Val string&nbsp; &nbsp; Children Children}type Children struct {&nbsp; &nbsp; Child []Child}type Child struct {&nbsp; &nbsp; Val string}也贴在这里：去游乐场请注意，您的代码可以使用这种 XML 结构（在将变量名从 更改Children为 之后Child）：<Parent>&nbsp; &nbsp; <Val>Hello</Val>&nbsp; &nbsp; <Child><Val>Hello</Val></Child>&nbsp; &nbsp; <Child><Val>Hello</Val></Child>&nbsp; &nbsp; <Child><Val>Hello</Val></Child></Parent>