相同键的两个数组值相减，并在php中得到匹配和不匹配值的结果
我有两个数组，如 $a 和 $b。我想为相同的键从 $a 减去 $b 。我也想看到两个数组的不匹配键和减法结果。只会减去匹配的键。是否可以不使用 foreach 循环？非强制要求必须无循环求解。但如果没有循环就可能更好。示例数组在下面。
$a=Array
(
[1] => 4.00
[2] => 3.00
[3] => 8.00
[4] => 4.88
[5] => 7.88
[10] => 17.88
)
$b=Array
(
[1] => 2.00
[3] => 4.00
[4] => 2.88
[7] => 5.00
[8] => 6.00
)
我想要这样的结果
$result=array(
[1] => 2.00
[2] => 3.00
[3] => 4.00
[4] => 2.00
[5] => 7.88
[7] => 5.00
[8] => 6.00
[10] => 17.88
);
我的代码是：
$res1=$res2=$res3=array();
foreach( $a as $k1=>$v1 ){
foreach($b as $k2=>$v2){
if($k1==$k2){
$res1[$k1]=$v2-$v1;
}else{
$res2[$k2]=v2;
$res3[$k1]=v1;
}
}
}
$res[]=array_merge($res1,$res2,$res3);
echo "<pre>"; print_r($res); echo "</pre>";
但它没有给出我想要的正确结果。
慕少森浏览 318回答 3
3回答
-
一只名叫tom的猫
正如评论中提到的，array_walk本质上仍然是一个循环，因为它迭代每个元素。我已经记录了每一步的代码，但基本思想是创建一个合并的数组，然后更改重复项的值。有更有效的方法来解决这个问题，但这说明了一种基本方法。我还应该指出，因为这是使用array_walk匿名函数（闭包），我们必须传入它需要的任何变量（... use (...)）。如果你使用一个foreach循环（或for），你不会需要做到这一点，你可以访问的$output，$first和$second直接。https://3v4l.org/WD0t4#v7125<?php$first = [ 1 => 4.00, 2 => 3.00, 3 => 8.00, 4 => 4.88, 5 => 7.88, 10 => 17.88];$second = [ 1 => 2.00, 3 => 4.00, 4 => 2.88, 7 => 5.0, 8 => 6.00];// Merge the 2 original arrays and preserve the keys// https://stackoverflow.com/q/17462354/296555// The duplicate items' value will be clobbered at this point but we don't care. We'll set them in the `array_walk` function.$output = $first + $second;// Create an array of the duplicates. We'll use these keys to calculate the difference.$both = array_intersect_key($first, $second);// Foreach element in the duplicates, calculate the difference.// Notice that we're passing in `&$output` by reference so that we are modifying the underlying object and not just a copy of it.array_walk($both, function($value, $key) use (&$output, $first, $second) { $output[$key] = $first[$key] - $second[$key];});// Finally, sort the final array by its keys.ksort($output);var_dump($output);// Output//array (size=8)// 1 => float 2// 2 => float 3// 3 => float 4// 4 => float 2// 5 => float 7.88// 7 => float 5// 8 => float 6// 10 => float 17.88以及使用foreach循环的强制性精简版本。<?php$first = [ 1 => 4.00, 2 => 3.00, 3 => 8.00, 4 => 4.88, 5 => 7.88, 10 => 17.88];$second = [ 1 => 2.00, 3 => 4.00, 4 => 2.88, 7 => 5.0, 8 => 6.00];$output = $first + $second;foreach (array_keys(array_intersect_key($first, $second)) as $key) { $output[$key] = $first[$key] - $second[$key];}ksort($output);var_dump($output);// Output//array (size=8)// 1 => float 2// 2 => float 3// 3 => float 4// 4 => float 2// 5 => float 7.88// 7 => float 5// 8 => float 6// 10 => float 17.88 -
ABOUTYOU
你非常接近！$count = count($a) + count($b); // figure out how many times we need to loop - count total # of elementsfor ( $key = 1; $key <= $count ; $key++ ){ if ( isset($a[$key]) && isset($b[$key]) ) $result[$key] = number_format(abs($a[$key] - $b[$key]), 2); elseif ( isset($a[$key]) ) $result[$key] = number_format($a[$key], 2); elseif ( isset($b[$key]) ) $result[$key] = number_format($b[$key], 2);}"number_format" 和 "abs" 函数只是为了使输出看起来与您所说的完全一样。 -
侃侃无极
请尝试使用以下代码。希望它会给你想要的输出。$res1=$res2=$res3=array(); foreach( $a as $k1=>$v1 ){ if(isset($b[$k1])){ $res1[$k1]=$a[$k1]-$b[$k1]; }else{ $res2[$k1]=$v1; } } $res3=array_diff_key($b, $a); $result = array_replace_recursive($res1,$res2,$res3); echo "<pre>"; print_r($result); echo "</pre>";
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