肥皂起泡泡
当数据收集不统一时,这有点挑战。我不熟悉 Timex,无法找到任何可能有帮助的软件包。这可能会帮助你。我编写了一些处理每个特定情况的函数。import datetimefrom pprint import pprintdates = ['2018-07-09', '2018-W15', '2018-02', '2018-04-06', '2018-W15', '2018-02', '2015-09', '2018-09-27 INTERSECT P5D', 'FUTURE_REF', 'FUTURE_REF', 'PXY', 'THIS P1D INTERSECT 2018-09-28', {'end': 'XXXX-06', 'begin': 'XXXX-04'}, '2014-03-19', '2018-08-02']FORMAT = '%Y-%m-%d'def get_simple_date(item, strformat=FORMAT): try: return (True, datetime.datetime.strptime(item, strformat)) except (ValueError, TypeError): return (False, item)def get_from_split(is_resolved, item): if is_resolved: return (is_resolved, item) try: tokens = item.split(' ') are_resolved, items = zip(*(get_simple_date(token) for token in tokens)) if any(are_resolved): # assume one valid token result, = (item for item in items if isinstance(item, datetime.datetime)) return (True, result) except (ValueError, AttributeError): pass return (False, item)def get_from_no_day(is_resolved, item): if is_resolved: return (is_resolved, item) if not 'W' in item: try: return (True, datetime.datetime.strptime(f'{item}-01', FORMAT)) except ValueError: pass return (False, item)def get_from_w_date(is_resolved, item): if is_resolved: return (is_resolved, item) if 'W' in item: return (True, datetime.datetime.strptime(f'{item}-1', "%Y-W%W-%w")) return (is_resolved, item)collection1 = (get_simple_date(item) for item in dates)collection2 = (get_from_split(*args) for args in collection1)collection3 = (get_from_no_day(*args) for args in collection2)collection4 = (get_from_w_date(*args) for args in collection3)pprint([d for is_resolved, d in collection4 if is_resolved], indent=4)输出:[ datetime.datetime(2018, 7, 9, 0, 0), datetime.datetime(2018, 4, 9, 0, 0), datetime.datetime(2018, 2, 1, 0, 0), datetime.datetime(2018, 4, 6, 0, 0), datetime.datetime(2018, 4, 9, 0, 0), datetime.datetime(2018, 2, 1, 0, 0), datetime.datetime(2015, 9, 1, 0, 0), datetime.datetime(2018, 9, 27, 0, 0), datetime.datetime(2018, 9, 28, 0, 0), datetime.datetime(2014, 3, 19, 0, 0), datetime.datetime(2018, 8, 2, 0, 0)]