将 String 转换为 String[] 但不在撇号中使用逗号

Question

我有一个字符串

String strValue = "city, image, N'Hello, World , It Rain', picture";

我想转换为 String[] 并且我使用了 strValue.Split(',')

结果：

[

city, 

image, 

N'Hello, 

World, 

It Rain', 

picture

]

但我不想拆分 N'Hello, World , It Rain'

我想要的结果是：

[

city,

image,

N'Hello, World , It's Rain',

picture

]

谢谢大家。

Answer 1

您可以使用以下行将其拆分为使用多个字符作为分隔符的数组，因为您的字符串值是使用逗号后跟空格分隔的，如您的示例所示。String[] strValues = strValue.Split(new string[] { ", " }, StringSplitOptions.None);这是一个DotNetFiddle编辑 - 鉴于需求的突然变化......如果你不关心结果的顺序，并且你想提取句子，因为它们都再次('N<sentence>')采用相同的格式，我们可以使用这样的东西来快速提取值：String strValue = "city, image, N'Hello, World , It Rain', picture";// Match the sentences by N'{text}'var strValues = Regex.Match(strValue, "(?<=N')(.*?)(?=')");// Remove the sentences from the stringforeach(var matchedVal in strValues.Captures){&nbsp; &nbsp; var toRepl = String.Format("N'{0}', ", matchedVal.ToString());&nbsp; &nbsp; strValue = strValue.Replace(toRepl, "");}// Split the remainder of the stringList<string> strOtherValues = strValue.Split(new string[] { ", " }, StringSplitOptions.None).ToList();// Add all sentences to words listforeach (var matchedVal in strValues.Captures){&nbsp; &nbsp; strOtherValues.Add(matchedVal.ToString());}

Answer 2

嗯，这是一个完美的烂摊子；可能也有糟糕的表现。但至少它似乎可以做你想做的事（还没有测试过很多极端情况）。问题是，您需要以某种方式区分“内部”或“外部”原始字符串的“转义”部分。如果您在“内部”，则不应通过分隔符进行正常拆分。public static IEnumerable<string> MySpecialSplit(string value, string separator, string escapeStart, string escapeEnd){&nbsp; &nbsp; var result = new List<string>();&nbsp; &nbsp; var start = value.StartsWith(separator) ? separator.Length : 0;&nbsp; &nbsp; var inEscape = false;&nbsp; &nbsp; for (var i = start; i < value.Length - separator.Length; i++)&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; if (inEscape && value.Length > i + escapeEnd.Length && value.Substring(i, escapeEnd.Length).Equals(escapeEnd))&nbsp; &nbsp; &nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; inEscape = false;&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; else if (!inEscape && value.Length > i + escapeStart.Length && value.Substring(i, escapeStart.Length).Equals(escapeStart))&nbsp; &nbsp; &nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; inEscape = true;&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; if (!inEscape && value.Substring(i, separator.Length).Equals(separator))&nbsp; &nbsp; &nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; result.Add(value.Substring(start, i - start));&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; i += separator.Length;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; start = i;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; i--;&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }&nbsp; &nbsp; if (start < value.Length - separator.Length)&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; var rest = value.Substring(start);&nbsp; &nbsp; &nbsp; &nbsp; if (rest.EndsWith(separator))&nbsp; &nbsp; &nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; rest = rest.Substring(0, rest.Length - separator.Length);&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; result.Add(rest);&nbsp; &nbsp; }&nbsp; &nbsp; return result;}像这样使用它：var splitted = MySpecialSplit("city, image, N'Hello, World , It's Rain', picture", ", ", "N'", "',");Console.WriteLine(string.Join(Environment.NewLine, splitted));结果：cityimageN'Hello, World , It's Rain'picture

Answer 3

似乎您的字符串格式已知有 4 个字段逗号分隔，在这种情况下使用正则表达式知道第三个字段可能有逗号：&nbsp; &nbsp; String strValue = "city, image, N'Hello, World , It Rain', picture";&nbsp; &nbsp; Pattern PATTERN = Pattern.compile("([^,]+), ([^,]+), (.+), ([^,]+)");&nbsp; &nbsp; Matcher matcher = PATTERN.matcher(strValue);&nbsp; &nbsp; if (matcher.find()) {&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(matcher.group(1));&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(matcher.group(2));&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(matcher.group(3));&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(matcher.group(4));&nbsp; &nbsp; }