展平对象并将多个对象推送到数组
我正在尝试将数组内的多个对象展平。它不断将其扁平化为一个数组。我希望它在数组中有多个对象，但也希望除键和值之外的所有内容都变平。
这是名为“livedata”的当前数组。
[
{
"earningsFileId": {
"value": 1234
},
"paymentType": {
"value": "Session",
"errors": [
{
"id": 802462,
"message": "Invalid Combination",
"status": "Processing"
}
]
},
"detailStatus": {
"value": "Processing"
}
},
{
"earningsFileId": {
"value": 5678
},
"paymentType": {
"value": "Session",
"errors": [
{
"id": 802462,
"message": "Invalid Combination",
"status": "Processing"
}
]
},
"detailStatus": {
"value": "Processing"
}
}
]
这是我试图实现的输出。
[
{
"earningsFileId": 1234,
"paymentType": "Session",
"detailStatus": "Processing"
},
{
"earningsFileId": 1234,
"paymentType": "Session",
"detailStatus": "Processing"
}
]
data = [];
Object.values(livedata).map((value, keys) => {
Object.keys(value).forEach((key) => {
data[key] = livedata[keys][key]['value']
})
});
慕仙森1回答
-
哆啦的时光机
您需要从livedata. 你可以使用每个键-值对Object.entries和reduce数组到你想要的对象：const livedata = [{ "earningsFileId": { "value": 1234 }, "paymentType": { "value": "Session", "errors": [{ "id": 802462, "message": "Invalid Combination", "status": "Processing" }] }, "detailStatus": { "value": "Processing" } }, { "earningsFileId": { "value": 5678 }, "paymentType": { "value": "Session", "errors": [{ "id": 802462, "message": "Invalid Combination", "status": "Processing" }] }, "detailStatus": { "value": "Processing" } }];const result = livedata.map(d => Object.entries(d).reduce((acc, [k, v]) => { acc[k] = v.value; return acc; }, {}))console.log(result);
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相关分类
JavaScript