错误：exportArchive：无法读取数据，因为它的格式不正确

Question

我有这个不是我写的脚本，它应该构建.ipa不同构建风格的 s：

import path from "path";

import { execSync } from "child_process";

import { name, iosDirectory } from "../../app.json";

import { version } from "../../package.json";

import { resolveFromRoot, distDir, createLogger } from "../build";

const getProcessOptions = () => {

  return {

    env: Object.assign({}, process.env, {

      // used to skip packager, since we default to release bundler is built in

      RCT_NO_LAUNCH_PACKAGER: true,

      CI_IOS_VERSION_NAME: version

      // CI_IOS_BUILD_NUMBER: build,

    })

  };

};

const buildProcess = ({ xcodebuildArgs }) => {

  return `xcodebuild ${xcodebuildArgs.join(" ")}`;

};

const archiveProject = ({

  xcodeProject,

  scheme,

  configuration = "Release",

  buildPath,

  archivePath

}) => {

  const xcodebuildArgs = [

    xcodeProject.isWorkspace ? "-workspace" : "-project",

    xcodeProject.name,

    "-configuration",

    configuration,

    "-scheme",

    scheme,

    "-derivedDataPath",

    buildPath,

    "-archivePath",

    archivePath,

    "archive",

    "-UseModernBuildSystem=NO"

  ];

  return buildProcess({

    xcodebuildArgs

  });

};

const exportProject = ({ archivePath, exportOptionsPlist }) => {

  const xcodebuildArgs = [

    "-archivePath",

    archivePath,

    "-exportPath",

    distDir,

    "-exportOptionsPlist",

    exportOptionsPlist,

    "-exportArchive"

  ];

  return buildProcess({

    xcodebuildArgs

  });

};

const run = () => {

  const logger = createLogger("ios builds");

  const projectPath = resolveFromRoot(

    path.join(iosDirectory, `${name}.xcworkspace`)

  );

Answer 1

我通过运行以下命令解决了这个问题：gem list | grep sqlite3gem install sqlite3 --platform=rubyrvm use system --default