打破基本python的循环

Question

我已经为此工作了一段时间。我已经能够让这部分工作，但从来没有完成。最终目标是将用户循环回另一个游戏，如果他们愿意的话。我认为问题出在我的 break 语句上，但我不确定如何绕过它。我已经包含了我所有的代码，以便可以发现任何错误。抱歉，如果已经回答了这个问题，我找不到存在此类问题的页面。

def game():

    import random

    from random import randint

    n = randint(1, 10)

    print('Enter a seed vlaue: ')

    the_seed_value = input(' ')

    random.seed(the_seed_value)

    guessesTaken = 0

    print("what is your name?")

    myName = input("")

    guess = int(input("Enter an integer from 1 to 99: "))

    while n != "guess":

        if guess < n:

            print ("guess is low")

            guessesTaken = guessesTaken + 1

            guess = int(input("Enter an integer from 1 to 99: "))

        elif guess > n:

            print ("guess is high")

            guessesTaken = guessesTaken + 1

            guess = int(input("Enter an integer from 1 to 99: "))

        else:

            print ("Congradulations " + myName +  " you guessed it in " + str(guessesTaken) + " guesses!") 

            break 

    print('Want to play agian? y/n')

    answer = input(" ")

    if answer == "n":

        print ("Ok, See you next time!")

    elif answer == "y":

        print("Starting new game!")

        game()

def main():

    game()

if __name__ == "__main__":

    main()

Answer 1

一方面，@kerwei 正确指出您的while线路有问题，需要从 更改while n != "guess":为while n != guess:。对于两个，当玩家正确猜测时，你的 while 循环就会得到满足，绕过这Congrats条线。由于游戏目前的结构是保持循环直到玩家猜对了，一个简单的解决方法是else:从循环中删除该行并在之后放置胜利语句。那是，def game()&nbsp; &nbsp; ...&nbsp; &nbsp; while n != guess:&nbsp; &nbsp; &nbsp; &nbsp; if guess < n:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ...&nbsp; &nbsp; &nbsp; &nbsp; elif guess > n:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ...&nbsp; &nbsp; print('Congrats!')&nbsp; &nbsp; print('play again?')&nbsp; &nbsp; ...&nbsp;