如何将二进制、八进制和四进制列表转换为十进制列表？

Question

我需要将三个列表转换为十进制列表以检查其中的最大值和最小值。我该怎么做？示例列表：

binary_list = [0, 0, 0, 0, 0, 1, 1, 10, 10, 11, 100, 100, 11, 10, 0]

quaternary_list = [-11, -33, -22, -132, -220, -310]

octal_list = [62, -220, -36, 5, 0, 1, -12]

Answer 1

如果我正确理解您的问题，您可以执行以下操作（在线尝试）：binary_list = [0, 0, 0, 0, 0, 1, 1, 10, 10, 11, 100, 100, 11, 10, 0]quaternary_list = [-11, -33, -22, -132, -220, -310]octal_list = [62, -220, -36, 5, 0, 1, -12]def list_to_decimal(lst, base):    return [int(str(item), base) for item in lst]print(list_to_decimal(binary_list, 2)) # => [0, 0, 0, 0, 0, 1, 1, 2, 2, 3, 4, 4, 3, 2, 0]print(list_to_decimal(quaternary_list, 4)) # => [-5, -15, -10, -30, -40, -52]print(list_to_decimal(octal_list, 8)) # => [50, -144, -30, 5, 0, 1, -10]它使用一个list_to_decimal接受列表lst和基数的函数工作base，然后使用列表推导式将 的每个元素解释lst为 的数量base。这是否回答你的问题？

Answer 2

你可以这样做。binary_list = [0, 0, 0, 0, 0, 1, 1, 10, 10, 11, 100, 100, 11, 10, 0]quaternary_list = [-11, -33, -22, -132, -220, -310]octal_list = [62, -220, -36, 5, 0, 1, -12]binary_list_do_dec = [int(str(i), 2) for i in binary_list]quaternary_list_do_dec = [int(str(i), 4) for i in quaternary_list]octal_list_do_dec = [int(str(i), 8) for i in octal_list]print(binary_list_do_dec)print(quaternary_list_do_dec)print(octal_list_do_dec)输出看起来像：[0, 0, 0, 0, 0, 1, 1, 2, 2, 3, 4, 4, 3, 2, 0][-5, -15, -10, -30, -40, -52][50, -144, -30, 5, 0, 1, -10]