如何打印getter String而不将null作为输出？

Question

每当我使用 showMessage() 时，我都会得到空值；我相信这是因为我在方法结束时返回了 c 。有没有办法打印出 getName() 而不是在 main 方法中，就像 getName() 在 showMessage() 方法中一样。. 这是我的候选人类

public class Candidate {

private String name;

private int votes;

//default constructor

public Candidate() {

String name = "Not Available! ";

int votes = 0; 

}

//overloaded constructor

public Candidate(String _name, int _votes){

  name  = _name;

  votes = _votes;

}

//getter

public String getName(){return name;}

public int getVotes(){return votes;}

//setter

public void incrementVote(){

  votes = votes + 1;

}

public void setName(String _name){

    name =_name;

}

public void print(){

    System.out.println("To vote for " + name);

}

}

这是我的主要

import java.util.*;

public class Election {

public static void main(String args[]){

System.out.println("Welcome to the polls! ");

 Candidate c1 = new Candidate();

 Candidate c2 = new Candidate();

 Candidate c3 = new Candidate();

 Candidate c4 = new Candidate();

c1 = inputCandidate();

c2 = inputCandidate();

c3 = inputCandidate();

c4 = inputCandidate();

c1 = showMessage();

}

private static Candidate inputCandidate(){

    Scanner sc = new Scanner(System.in);

    String inputN;

    Candidate c = new Candidate();

    System.out.println("Enter candidate");

    inputN = sc.nextLine();

    c.setName(inputN);

   return c;

}

private static Candidate showMessage(){

    Candidate c = new Candidate();

    System.out.println(c.getName());

    return c;

}

}

Answer 1

只需更换c1 = showMessage();和，showMessage(c1);并修改方法showMessage如下private static void showMessage(Candidate c ){        System.out.println(c.getName());}同样，您可以使用showMessage打印剩余对象的消息，例如showMessage(c2);showMessage(c3);showMessage(c4);