在 Javascript 中使用 PHP 二维数组

Question

在 php 我有这个数组

$MAtoJS[] = array('Max','Mustermann','N','A80');

$MAtoJS[] = array('Michaela','May','N','A78');

$MAtoJS[] = array('Hans','Gerstelhuber','N','M12');

$MAtoJS[] = array('Alfred E.','Neumann','N','T25');

$MAtoJS[] = array('James','Bond','N','M72');

仍然在 php 部分我为 js 准备了数组

$MAarrayForJS = json_encode(json_encode($MAForJS));

在 javascript 部分，我创建了一个 js-array

var MAarray = new Array(<?php echo $MAarrayForJS; ?>); alert(MAarray)

MAarray 的内容是

[["Max","Mustermann","N","A80"],["Michaela","May","N","A78"],["Hans","Gerstelhuber","N","M12"],["Alfred E.","Neumann","N","T25"],["James","Bond","N","M72"]]

使用

console.log(MAarray[0]);

例如，我试图通过此代码获取 Hans 的名字

var FirstName = MAarray[0][2][1];

这导致 console.log 中的“未定义”。

如何访问特定数组中的特定值，在这种情况下，将 var FirstName 设置为第三个“子数组”中的值“Hans”？

Answer 1

请注意，数组是2 维而不是3 维，您访问的第 3 维将始终产生未定义，请查看下面的代码片段，其中获取值，并根据要求进行更改：let MAarray = [["Max","Mustermann","N","A80"],["Michaela","May","N","A78"],["Hans","Gerstelhuber","N","M12"],["Alfred E.","Neumann","N","T25"],["James","Bond","N","M72"]];console.log(MAarray[2][0]);MAarray[2][0] = "New Name";console.log(MAarray[2][0]);

Answer 2

你在找这个……？$MAtoJS = [];$MAtoJS[] = array('Max','Mustermann','N','A80');$MAtoJS[] = array('Michaela','May','N','A78');$MAtoJS[] = array('Hans','Gerstelhuber','N','M12');$MAtoJS[] = array('Alfred E.','Neumann','N','T25');$MAtoJS[] = array('James','Bond','N','M72');$MAarrayForJS = json_encode($MAtoJS);?><script>&nbsp; &nbsp; var MAarray = <?php echo $MAarrayForJS; ?>;&nbsp; &nbsp; console.log(MAarray[0][0]); // Max</script>

Answer 3

尝试var&nbsp;FirstName&nbsp;=&nbsp;MAarray[2][1];您似乎正在尝试访问二维数组的第三层。