从视图中的类中的 url 读取字符串 (APIView)

我的模式中有一个如下所示的网址


urlpatterns = [

...

    path('rest-auth/registration/account-confirm-email/<str:key>', VerifyEmailView.as_view(), name='account_confirm_email'),

...

]

我需要能够从此示例网址传递密钥(“MjU:1ggiI:923vm1cLboPQk9TX1f0aywDWBs8”):


http://127.0.0.1:8000/rest-auth/registration/account-confirm-email/MjU:1ggiiI:923vm1cLboPQk9TX1f0aywDWBs8/


以下观点:


class VerifyEmailView(APIView):

    permission_classes = (AllowAny,)

    allowed_methods = ('POST','GET', 'OPTIONS', 'HEAD')

....

    def get(self, request, *args, **kwargs):

        serializer = self.get_serializer(data=request.data)

        serializer.is_valid(raise_exception=True)

        '''key is used here'''

        self.kwargs['key'] = serializer.validated_data['key']

        confirmation = self.get_object()

        confirmation.confirm(self.request)

....

有人请告诉我如何在此视图中访问我的密钥?


翻翻过去那场雪
浏览 187回答 4
4回答

茅侃侃

您可以使用path = request.pathpath_vals = path.split('/')key = path_vals[-2]
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