去意外的字符串文字

Question

这是我在 Go 中的代码，我猜一切都是正确的......

package main

import(

"fmt"

"encoding/json"

"net/http"

)

type Payload struct {

    Stuff Data

}

type Data struct {

    Fruit Fruits

    Veggies Vegetables

}

type Fruits map[string]int

type Vegetables map[string]int

func serveRest(w http.ResponseWriter, r *httpRequest){

    response , err := getJsonResponse()

    if err != nil{

        panic(err)

    }

    fmt.println(w, string(response))

}

func main(){

http.HandleFucn("/", serveRest)

http.ListenAndServe("localhost:1337",nil)

}

func getJsonResponse() ([]byte, error){

fruits := make(map[string]int)

fruits["Apples"] = 25

fruits["Oranges"] = 11

vegetables := make(map[string]int)

vegetables["Carrots"] = 21

vegetables["Peppers"] = 0

d := Data{fruits, vegetables}

p := Payload{d}

return json.MarshalIndent(p, "", "  ")

}

这是我得到的错误

API_Sushant.go:31: syntax error: unexpected string literal, expecting semicolon or newline or }

谁能告诉我错误是什么请....

Answer 1

您的示例中有一些小错误。修复这些之后，您的示例为我运行而没有unexpected string literal错误。此外，如果要将 JSON 写入http.ResponseWriter，则应更改fmt.Println为fmt.Fprintln如下面的第 2 部分所示。(1) 轻微错别字# Error 1: undefined: httpRequestfunc serveRest(w http.ResponseWriter, r *httpRequest){# Fixed:func serveRest(w http.ResponseWriter, r *http.Request){# Error 2: cannot refer to unexported name fmt.printlnfmt.println(w, string(response))# Fixed to remove error. Use Fprintln to write to 'w' http.ResponseWriterfmt.Println(w, string(response))# Error 3: undefined: http.HandleFucnhttp.HandleFucn("/", serveRest)# Fixedhttp.HandleFunc("/", serveRest)(2) HTTP Response 中返回 JSON因为fmt.Println写入标准输出并fmt.Fprintln写入提供的 io.Writer，要在 HTTP 响应中返回 JSON，请使用以下内容：fmt.Fprintln(w, string(response))