慕后森
您可以创建一个function并在 ajaxsuccess函数上调用它,最后有两种方法可以将值放入phpbyform submit或ajax。我使用了 ajax 方法,即: function result(r){//"r" have response value //pass to ajax alert("i'm in"); $.ajax({ type: "POST", url: "page1.php", data: { 'value': r}, success: function(response){ alert("done"); }, error: function (jqXHR) { console.log(jqXHR); alert("There was a problem"); }}); }$.ajax({ type: "POST", url: "page.php", success: function(response){ //passing response value to function "result" result(response); }, error: function (jqXHR) { console.log(jqXHR); alert("There was a problem"); } }); 现在page1.php写如下:<?phpsession_start();//putting value in session$_SESSION['url'] = $_POST['value']; ?>