Android - JSON 解析不使用“setText”显示数据

Question

我有以下 JSON 信息。

{

    "version": 2,

    "locations": [{

        "id": "750",

        "geo": {

            "name": "Lord Howe Island",

            "state": "Lord Howe Island",

            "country": {

                "id": "au",

                "name": "Australia"

            },

            "latitude": -31.557,

            "longitude": 159.086

        },

        "astronomy": {

            "objects": [{

                "name": "moon",

                "days": [{

                    "date": "2018-09-05",

                    "events": [],

                    "moonphase": "waningcrescent"

                }]

            }]

        }

    }]

}

我想要做的是将 JSON 中的一些细节（不是全部）打印到 textView，所以我想要的输出如下：

名称：豪勋爵岛国家：澳大利亚月相：残月

但是，在解析要在 textView 中打印的信息时，我没有任何运气。我目前正在使用以下代码：

JSONArray JA = new JSONArray(data);

        for (int i = 0; i < JA.length(); i++) {

            JSONObject JO = (JSONObject) JA.get(i);

            JSONObject geo = JO.getJSONObject("geo");

            JSONObject astronomy = JO.getJSONObject("astronomy");

            singleParsed = "Name:" + geo.get("name") + "\n" +

                    "Latitude:" + JO.get("latitude") + "\n" +

                    "Longitude:" + JO.get("longitude") + "\n" +

                    "Phase: " + astronomy.get("moonphase") + "\n";

        }

然后显示数据如下：

protected void onPostExecute(Void aVoid) {

        super.onPostExecute(aVoid);

        MainActivity.fetcheddata.setText(this.singleParsed);

    }

}

我可以只使用打印所有数据

MainActivity.fetcheddata.setText(this.data);

但是我也看到了 textView 和 ALL Information 中的标签，而不是我所追求的几个标签。

我究竟做错了什么？

非常感谢所有帮助

Answer 1

您遇到的问题是您正在尝试使用 JSONObjects，即使位置是一个数组，对象也是如此。为此，您需要像这样迭代数组：&nbsp; &nbsp; JSONObject jo = new JSONObject(yourData);&nbsp; &nbsp; JSONArray locations = jo.getJSONArray("locations");&nbsp; &nbsp; for (int i = 0; i < locations.length(); ++i) {&nbsp; &nbsp; &nbsp; &nbsp; //iterate over each key, etc.&nbsp; &nbsp; }在我看来，在一天结束时，如果您更改密钥、添加密钥等，这将是一团糟，并且维护起来很痛苦。我建议您查看 GSON 之类的东西，然后只创建数据的视图模型你要。最后你会得到这样的东西：List<T> yourObjects = gson.fromJson(jsonReader, X[].class);然后您可以单独访问您想要的任何属性。

Answer 2

假设您的 json 数据原样以及您在上面写的输出：&nbsp; &nbsp; JSONArray locations = data.getJSONArray("location");&nbsp; &nbsp; JSONObject loc = locations.getJSONObject(0);&nbsp; &nbsp; JSONObject geo = loc.getJSONObject("geo");&nbsp; &nbsp; JSONObject country = geo.getJSONObject("country");&nbsp; &nbsp; JSONObject astronomy = loc.getJSONObject("astronomy");&nbsp; &nbsp; JSONObject objects = astronomy.getJSONArray("objects").getJSONObject(0);&nbsp; &nbsp; JSONObject day = objects.getJSONArray("days").getJSONObject(0);&nbsp; &nbsp; StringBuilder result = new StringBuilder();&nbsp; &nbsp; String singleParsed = "Name:" + geo.getString("name") + "\n" +&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "Country: " + country.getString("name") +&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "Moon Phase: " + astronomy.getString("moonphase") + "\n";

Answer 3

不能moonphase直接从astronomy, []将定义一个数组，所以你可以这样做：&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "astronomy": {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "objects": [{&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "name": "moon",&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "days": [{&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "date": "2018-09-05",&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "events": [],&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; "moonphase": "waningcrescent"&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }]&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }]&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }JSONObject astronomy = JO.getJSONObject("astronomy");JSONArray objects = astronomy.getJSONArray("objects");JSONArray days = objects.getJSONObject(0).getJSONArray("days");JSONObject moonphase = days.getJSONObject(0).get("moonphase");