我正在尝试通过 render_to_response 将一个 json 文件传递给前端。前端不是 django 模板,它是用 JS、HTML 等编码的。我遇到了一些奇怪的错误。任何人都可以帮助我。我附上了代码和回溯。
return render_to_response('ModelView.html', json.dumps(newDict))
Traceback (most recent call last):
File "C:\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\handlers\exception.py", line 35, in inner
response = get_response(request)
File "C:\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\handlers\base.py", line 128, in _get_response
response = self.process_exception_by_middleware(e, request)
File "C:\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\handlers\base.py", line 126, in _get_response
response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "C:\PythonWorkspace\ScApp\ScApp2\views.py", line 78, in ScorecardApp20
return render_to_response('ModelView.html', json.dumps(newDict))
File "C:\Users\kxc89\AppData\Local\Programs\Python\Python37\lib\site-packages\django\shortcuts.py", line 27, in render_to_response
content = loader.render_to_string(template_name, context, using=using)
File "C:\AppData\Local\Programs\Python\Python37\lib\site-packages\django\template\loader.py", line 62, in render_to_string
return template.render(context, request)
File "C:\AppData\Local\Programs\Python\Python37\lib\site-packages\django\template\backends\django.py", line 59, in render
context = make_context(context, request, autoescape=self.backend.engine.autoescape)
File "C:\AppData\Local\Programs\Python\Python37\lib\site-packages\django\template\context.py", line 274, in make_context
raise TypeError('context must be a dict rather than %s.' % context.__class__.__name__)
TypeError: context must be a dict rather than str.
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