查看“Fluent Python”书中解释 的“双向隧道”功能的以下示例代码yield from,我有以下问题。
from collections import namedtuple
Result = namedtuple('Result', 'count average')
# the subgenerator
def averager(): # <1>
total = 0.0
count = 0
average = None
while True:
term = yield # <2>
if term is None: # <3>
break
total += term
count += 1
average = total/count
return Result(count, average) # <4>
# the delegating generator
def grouper(results, key): # <5>
while True: # <6>
results[key] = yield from averager() # <7>
# the client code, a.k.a. the caller
def main(data): # <8>
results = {}
for key, values in data.items():
group = grouper(results, key) # <9>
next(group) # <10>
for value in values:
group.send(value) # <11>
group.send(None) # important! <12>
print("wrapped up grouper")
print(results)
data = {
'girls;kg':
[40.9, 38.5, 44.3, 42.2, 45.2, 41.7, 44.5, 38.0, 40.6, 44.5],
'girls;m':
[1.6, 1.51, 1.4, 1.3, 1.41, 1.39, 1.33, 1.46, 1.45, 1.43],
'boys;kg':
[39.0, 40.8, 43.2, 40.8, 43.1, 38.6, 41.4, 40.6, 36.3],
'boys;m':
[1.38, 1.5, 1.32, 1.25, 1.37, 1.48, 1.25, 1.49, 1.46],
}
StopIteration当我用下面的委托生成器替换上面的委托生成器时,为什么会出现异常?
def grouper(results, key):
results[key] = yield from averager()
从我到目前为止所学到的,从理论上讲,删除while True应该没问题。group.send(None)将导致averager()协程break并返回Result(...),该 将被传递给委托生成器。然后委托生成器将通过将其分配Result(...)给results[key].
但正在发生的事情如下。
Traceback (mostrecent call last):
File "coroaverager3.py", line 111, in <module>
main(data)
File "coroaverager3.py", line 83, in main
group.send(None) # important! <12>
StopIteration
任何见解?
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