如何使用 java 中的 useDelimeter 从字符串中获取两个特定值？

Question

我正在尝试使用正则表达式从“line”字符串中获取两个玩家值并将它们插入到 player1 和 player2 中。

   try (BufferedReader in = new BufferedReader(new FileReader(file))) {

        String line;

        String player1;

        String player2;

        while ((line = in.readLine()) != null) {

            Scanner input = new Scanner(line);

            input.useDelimiter("(.* [a-z] )|\\sby ");

            if(line.toLowerCase().contains("kill")) {

                kill +=  1;

                //i would like to set the player1 and player2 here

            }                   

        }      

    }

我的文件片段（.txt）：

 13:37 Kill: 3 4 7: Oootsimo killed Dono da Bola by MOD_ROCKET_SPLASH

 13:37 Item: 5 weapon_rocketlauncher

 13:39 Item: 6 weapon_rocketlauncher

 13:40 Item: 7 ammo_rockets

 13:41 Item: 6 weapon_rocketlauncher

 13:41 Item: 4 weapon_rocketlauncher

 13:43 Kill: 2 5 6: Isgalamido killed Assasinu Credi by MOD_ROCKET

 13:45 Kill: 1022 7 22: <world> killed Mal by MOD_TRIGGER_HURT

 13:46 Kill: 4 3 7: Dono da Bola killed Oootsimo by MOD_ROCKET_SPLASH

 13:46 Kill: 6 2 6: Zeh killed Isgalamido by MOD_ROCKET

Answer 1

我不知道您的所有要求，但请尝试使用 Regexp：@Testpublic void test(){&nbsp; &nbsp; String string = "13:46 Kill: 6 2 6: Zeh killed Isgalamido by MOD_ROCKET";&nbsp; &nbsp; String regexp = "\\d+:\\d+ .*?([A-Za-z0-9]+) killed ([A-Za-z0-9]+).*?";&nbsp; &nbsp; String player1 = null;&nbsp; &nbsp; String player2 = null;&nbsp; &nbsp; Pattern p = Pattern.compile(regexp);&nbsp; &nbsp; Matcher m = p.matcher(string);&nbsp; &nbsp; if (m.find())&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; player1 = m.group(1);&nbsp; &nbsp; &nbsp; &nbsp; player2 = m.group(2);&nbsp; &nbsp; }&nbsp; &nbsp; assertEquals("Zeh", player1);&nbsp; &nbsp; assertEquals("Isgalamido", player2);}说明：\d+ - 一个数字，一次或多次.* - 任意字符，任意次数。这 '？' 表示“非贪婪”，因此匹配以下表达式的字符不会被覆盖([A-Za-z0-9]+) - '[]' 内的字符范围，一次或多次，被捕获一旦我确认这是你的意思，我会再次编辑我的答案