如何选择列表中的项目？

Question

我有：

我有两个这样的列表：

[('ELON_MUSK', True), ('BARACK_OBAMA', False), ('DONALD_TRUMP', False)]

[('ELON_MUSK', False), ('BARACK_OBAMA', True), ('DONALD_TRUMP', False)]

我想（问题）：

由于ELON_MUSK和BARACK_OBAMA是true我想给他们，并追加检索到的字符串，但我敢肯定，我不知道如何寻找的问题，正确的方面，因为我什么也没有发现这一点，因此要求在这里。

我希望发生：

People in this image: ELON_MUSK BARACK_OBAMA

我正在做：

for imagePath in imageArray:

        # Try comparing an unknown image

        unknown_image = face_recognition.load_image_file(imagePath)

        unknown_face = face_recognition.face_encodings(unknown_image)

        face_count = len(unknown_face)

        name_list = ""

        print("Checking: " + imagePath)

        print("----------------------------")

        for i in range(face_count):

                result = face_recognition.compare_faces(face_encodings, unknown_face[i])

                # Print the result as a list of names with True/False

                names_with_result = list(zip(face_names, result))

                print(names_with_result, end = '')

                print(" -- Checking face #" + str(i+1))

                # vvv I HAVE NO IDEA ABOUT THIS PART vvv

                if "True" in names_with_result:

                        #name_list = name_list + " name of the TRUE person";

        print("People in this image: " + name_list)

我越来越：

People in this image: 

Answer 1

# Separate lists of (name, is_in_image) tuples>>> a = [('ELON_MUSK', True), ('BARACK_OBAMA', False), ('DONALD_TRUMP', False)]>>> b = [('ELON_MUSK', False), ('BARACK_OBAMA', True), ('DONALD_TRUMP', False)]# Combine the lists>>> together = a + b# Create a list containing all names if the second element (is_in_image) is True>>> [name for name, is_in_image in together if is_in_image]['ELON_MUSK', 'BARACK_OBAMA']>>> print('People in this image: {}'.format(', '.join([name for name, is_in_image in together if is_in_image])))People in this image: ELON_MUSK, BARACK_OBAMA我认为你目前的做法主要的问题是，你的追加试验if 'True' in names_with_result，而不是if True in names_with_result... 'True' != True...>>> sample_result = ('ELON_MUSK', True)>>> 'True' in sample_resultFalse>>> True in sample_resultTrue第一个测试'True' in sample_result返回 False，然后不会触发您的附加逻辑，从而传递该元素。

Answer 2

你也可以这样做：l1 = [('ELON_MUSK', True), ('BARACK_OBAMA', False), ('DONALD_TRUMP', False)]l2 = [('ELON_MUSK', False), ('BARACK_OBAMA', True), ('DONALD_TRUMP', False)]# join the two listl1.extend(l2)# create a simple function that return a list of truef = lambda x: [i for i,j in x if j]print('{} is not {}'.format(*f(l1)))

Answer 3

试试这个：A= [('ELON_MUSK', True), ('BARACK_OBAMA', False), ('DONALD_TRUMP', False)]B= [('ELON_MUSK', False), ('BARACK_OBAMA', True), ('DONALD_TRUMP', False)]name_list  = ''.join([a[0]+' , '+b[0] for a in A for b in B if a[1]==True and b[1]== True])print("People in this image: "+ name_list)