最喜欢的食物 Java 程序出错了

Question

下面是我的Java程序。现在，程序正确运行的唯一方法是让最后一列最长。如果数组中的最后一列不是最长的，则输出不正确。例如，如果food数组在第二列中的元素比第三列中的元素多，如下所示：

String[][] food = {

        {"Bannana", "Apple", "Pear", "Orange"}, // fruits

        {"GreenBean", "Iceburg", "Spenach", "peas", "carrots", "potatoes", "beans"}, // vegetables 

        {"Steak",   "Baccon", "Beef", "TurkeyB", "TurkeyBacon", "Chicken"} // meats 

};

然后，例如，如果chicken输入作为输入，则输出是这样的：

Yo have no favorite food

Your favorite food is Chicken

而且，例如，如果输入是biscuit，那么输出是这样的：

Yo have no favorite food

Yo have no favorite food

那么，有没有办法只打印"Yo have no favorite food"一次或正确打印出最喜欢的食物，而最后一列不必最长？

这是代码：

package com.begg;

import java.util.*;

public class List {

    static Scanner sc = new Scanner(System.in);

    public static void main(String[] args) {

        String[][] food = {

                {"Bannana", "Apple", "Pear", "Orange"}, // fruits

                {"GreenBean", "Iceburg", "Spenach", "peas"}, // vegetables 

                {"Steak",   "Baccon", "Beef", "TurkeyB", "TurkeyBacon", "Chicken"} // meats 

        };

        for(int row = 0; row < food.length; row++) {

            for (int col = 0; col < food[row].length; col ++) {

                System.out.print(food[row][col] + ", ");

            }

            System.out.println();

        }

        System.out.println("Enter your favorite out of the options above:");

        String k = sc.next();

        loop2:

        for(int row2 = 0; row2<food.length; row2++) {

            for (int col2 = 0; col2< food[row2].length; col2++) {

                if (k.equalsIgnoreCase(food[row2][col2])) {

                    System.out.println("Your favorite food is " + food[row2][col2]);

                    break loop2;

                }

                else if (!(k.equalsIgnoreCase(food[row2][col2])) & col2== 5 ) {

                    System.out.println("Yo have no favorite food");

                }

            }

        }

    }

}

Answer 1

改变这部分：else if (!(k.equalsIgnoreCase(food[row2][col2])) & col2== 5 ) {&nbsp; &nbsp; System.out.println("Yo have no favorite food");}对此：else if (!(k.equalsIgnoreCase(food[row2][col2])) && row2 == food.length-1 && col2 == food[row2].length-1) {&nbsp; &nbsp; System.out.println("Yo have no favorite food");}应该做我认为你正在寻找的。编辑else if检查是否已检查数组的所有值（与哪一列更长无关），如果没有与输入匹配，则它将执行System.out.println("Yo have no favorite food");一次。