如何在Go中获取符文的十进制值？

Question

我需要解析一些字符串并通过将任何特殊字符解析为 'â' TO â 来清理它们。这是十进制编码。我知道如何使用this将其解析为 Unicode ，但我需要十进制代码。整个想法是替换那些特殊字符，如果它们包含特殊字符，则用转换返回整个字符串。例如：

text := "chitâra"

text := parseNCRs(text) //can be by reference

parseNCRs(&text) //or passing the pointer

fmt.Println(text) //Outputs: "chitâra"

Answer 1

遍历字符串以获取符文的数值。func escape(s string) string {&nbsp; var buf bytes.Buffer&nbsp; for _, r := range s {&nbsp; &nbsp; if r > 127 {&nbsp; &nbsp; &nbsp; &nbsp; fmt.Fprintf(&buf, "&#%d;", r)&nbsp; &nbsp; } else {&nbsp; &nbsp; &nbsp; &nbsp; buf.WriteRune(r)&nbsp; &nbsp; }&nbsp; }&nbsp; return buf.String()}playground如果您要转义 HTML 或 XML，那么您还应该处理其他特殊字符：func escape(s string) string {&nbsp; var buf bytes.Buffer&nbsp; for _, r := range s {&nbsp; &nbsp; if r > 127&nbsp; || r == '<' || r == '>' || r == '&' || r == '"' || r = '\'' {&nbsp; &nbsp; &nbsp; &nbsp; fmt.Fprintf(&buf, "&#%d;", r)&nbsp; &nbsp; } else {&nbsp; &nbsp; &nbsp; &nbsp; buf.WriteRune(r)&nbsp; &nbsp; }&nbsp; }&nbsp; return buf.String()}