如何使用 re.sub

Question

如果我明白你想要什么（计算这段时间内降雨量的绝对平均值），这应该可以解决问题：

number_of_months = 3

years_in_period = int(input("Please enter the number of years in the period. \n"))

total_rain = 0

for year in range(years_in_period):

    yearly_rain = 0

    print('Year', year+1) 

    print('−−−−−−−−−−−−−−−−−')

    for month in range(number_of_months):

        print('Month', month+1, end='')

        monthly_rain = float(input("Please enter rainfall for this month: \n"))

        yearly_rain += monthly_rain

        total_rain += monthly_rain

        average_yearly_rainfall = yearly_rain / number_of_months

    print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)

    print("Year total rain is", yearly_rain)

    print()

total_months = years_in_period * number_of_months

print("Absolute average of rain/month was", total_rain/total_months)

print("Absolute average of rain/year was", total_rain/years_in_period)

Answer 1

使用与您为结尾所做的相似的模式，并将它们串在一起。：test = re.sub(r'.* 159 ', '', re.sub(r' 265.*$', '', test))或者，您可以使用单个模式和re.findall：test = re.findall(r'^.*159 ([A-Z]+) 265.*$', test)