我如何将条目文本框的结果分配给一个变量，然后传递给后端的函数？

Question

我在使用 tkinter 编写刽子手游戏时遇到了一些问题，前端和后端分开并且都使用 OOP（我知道在后端使用 OOP 并不是真的有必要，它可能会更好作为图书馆，但我这样做是为了学习练习）。我是 tkinter 的新手，我想知道如何将输入文本框的结果分配给一个变量，然后传递给后端的函数。我还想知道我的 self.letter_row 和 self.guesses_left 标签是否会在后端更新时更新，尽管我在 game_gui() 开始时将它们分配到前面，但我不确定它们是否将自动执行此操作。这是所有前端代码...

from tkinter import *

from tkinter.ttk import *

import hangmanSkeleton as hm

class game_gui():

    def __init__(self,master):

        self.master = master

        master.title("Hangman")

        this_game = hm.Hangman()

        self.word = this_game.word

        self.letter_row = this_game.letter_row

        self.letters_guessed = this_game.letters_guessed

        self.guesses_left = this_game.guesses_left

        self.letter = StringVar()

        self.lbl_word = Label(master, text = "Welcome to Hangman!")

        self.lbl_word.grid(row = 0,padx = 10 , pady = 15, columnspan = 2)

        self.lbl_row = Label(master, text = self.letter_row)

        self.lbl_row.grid(row = 1, column = 0, padx = 15, pady = 10)

        self.lbl_guesses = Label(master, text = "Guesses Left: " + str(self.guesses_left))

        self.lbl_guesses.grid(row = 1, column = 1, padx = 15, pady = 10)

        self.entry_letter= Entry(master, textvariable = self.letter)

        self.entry_letter.grid(row = 2, padx = 10, pady = 20, columnspan = 2)

        self.guess_button = Button(master, text = "Guess Letter", command=lambda: this_game.guess_letter(self.letter))

        self.guess_button.grid(row = 3, padx = 10, pady = 10, columnspan = 2) 

root = Tk()

gui = game_gui(root)

root.mainloop()

这只是来自后端的函数，我试图在上面的 self.guess_button() 中工作..