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请参阅dict.update处的文档:使用其他键/值对更新字典,覆盖现有键。返回无。update()接受另一个字典对象或键/值对的可迭代对象(作为元组或其他长度为 2 的可迭代对象)。如果指定关键字参数,字典,然后用这些键/值对更新:d.update(red=1, blue=2)。例子:# dict expressiond = {"a":1, "b":2, "c":3}>>> {'a': 1, 'c': 3, 'b': 2}# multiple updates: no loop neededd.update( {"a" : 11, "b" : 22} )>>> {'a': 11, 'c': 3, 'b': 22}# multiple adds: no loop needed (also no '' around keys)d.update( A = 111, B = 22 )>>> {'a': 11, 'A': 111, 'c': 3, 'b': 22, 'B': 22}# updating all keys using loopfor k,v in d.items(): d[k]=v*2>>> {'a': 22, 'A': 222, 'c': 6, 'b': 44, 'B': 44} # add values to a list if same keys and not yet in# providing an existing key here would overwrite that onenew_ones = ( ("X",42), ("X",4711) )for k,v in new_ones: entry = d.setdefault(k,[]) entry.append(v)>>> {'a': 22, 'A': 222, 'c': 6, 'b': 44, 'B': 44, 'X': [42, 4711]}# no loop - update from iterable of key/value pairsnew_ones = ( ("i",42), ("j",4711) )d.update(new_ones)>>> {'a': 22, 'A': 222, 'c': 6, 'b': 44, 'i': 42, 'j': 4711, 'B': 44, 'X': [42, 4711]}