在 Python 的字典中分别计算大写和小写

Question

我试图做以下练习：考虑句子“Jim 很快意识到漂亮的礼服很贵”。创建一个字典 count_letters ，键由句子中的每个唯一字母组成，值由每个字母在这句话中的使用次数组成。在字典中分别计算大写和小写字母。

下面是我的代码，我认为它正在做练习所要求的，但出于某种原因，它仍然说我没有做对。任何想法，任何人？

sentence = 'Jim quickly realized that the beautiful gowns are expensive'

count_letters = {}

cnt_lowercase = 0

cnt_uppercase = 0

#write your code here!

for c in sentence:

    if c.islower():

        if (c in count_letters) == False:

            count_letters[c]={c:sentence.count(c)}

            cnt_lowercase += 1

    if c.isupper():

        if (c in count_letters) == False:

            count_letters[c]={c:sentence.count(c)}

            cnt_uppercase += 1

print(str(cnt_lowercase))

print(str(cnt_uppercase))

print(count_letters)

Answer 1

from collections import Countercount_letters = Counter('Jim quickly realized that the beautiful gowns are expensive')# this gives a dictionary of character -> count# if you need to skip spaces/punctuations (you probably do), use thiscount_letters = Counter(c for c in 'Jim quickly realized that the beautiful gowns are expensive' if c.isalpha())