想要自动化分拣过程。但解决不了。在同一个文件夹中有大约一千个具有相同扩展名的文件。想要将它们排序到不同的文件夹,例如:XXpattern1XX.XXX 文件到 [pattern1] 文件夹,Xpattern2XXX.XXX 文件到 [pattern2] 文件夹,pattern3XXXX.XXX 文件到 [pattern3] 文件夹等等。
有来自 SO 的脚本,但找不到原始帖子。但是现在还想不出怎么改。
#!/usr/bin/env python3
import os
import subprocess
import shutil
# --------------------------------------------------------
reorg_dir = "/path/to/directory_to_reorganize"
exclude = (".jpg") # for example
remove_emptyfolders = True
# ---------------------------------------------------------
for root, dirs, files in os.walk(reorg_dir):
for name in files:
subject = root+"/"+name
if name.startswith("."):
extension = ".hidden_files"
elif not "." in name:
extension = ".without_extension"
else:
extension = name[name.rfind("."):]
if not extension in exclude:
new_dir = reorg_dir+"/"+extension[1:]
if not os.path.exists(new_dir):
os.mkdir(new_dir)
n = 1; name_orig = name
while os.path.exists(new_dir+"/"+name):
name = "duplicate_"+str(n)+"_"+name_orig
n = n+1
newfile = new_dir+"/"+name
shutil.move(subject, newfile)
def cleanup():
filelist = []
for root, dirs, files in os.walk(reorg_dir):
for name in files:
filelist.append(root+"/"+name)
directories = [item[0] for item in os.walk(reorg_dir)]
for dr in directories:
matches = [item for item in filelist if dr in item]
if len(matches) == 0:
try:
shutil.rmtree(dr)
except FileNotFoundError:
pass
if remove_emptyfolders == True:
cleanup()
谢谢
凤凰求蛊
明月笑刀无情
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