C# 合并 4x 图像创建单个图像但使用这些特殊图像不起作用

Question

我已经编码为 4x 图像将合并为单个图像，尺寸将相加，以便最终图像确保它始终有空间容纳所有 4 个图像。

// Determining width and height

int widthF = Math.Max((globeVar.width1 + globeVar.width2), (globeVar.width3 + globeVar.width4));

int heightF = Math.Max((globeVar.height1 + globeVar.height2), (globeVar.height3 + globeVar.height4));

//Getting drawing objects ready

Image img = new Bitmap(widthF, heightF);

Graphics drawing = Graphics.FromImage(img);

//paint the background to check where image is not merged

drawing.Clear(Color.Blue);

drawing.InterpolationMode = System.Drawing.Drawing2D.InterpolationMode.High;

// Draw the image to the graphics to create the new image 

// Which will be used in the onpaint background                 

drawing.DrawImage(globeVar.image1, 0, 0);

drawing.DrawImage(globeVar.image2, (img.Width) / 2, 0);

drawing.DrawImage(globeVar.image3, 0, (img.Height) / 2);

drawing.DrawImage(globeVar.image4, (img.Width) / 2, (img.Height) / 2);

drawing.Save();

img.Save(@globeVar.savePath, ImageFormat.Png);                

drawing.Dispose();

现在代码实际上适用于以下 4 个图像：

https://imgur.com/a/4yrPWIs

但是当我使用这些图像时：

https://imgur.com/a/YBSEyBN

合并变成这样：

https://imgur.com/a/bhnkoi1

我到底错过了什么？

Answer 1

我自己找到了答案。看起来 DrawImage 方法没有考虑图像的默认大小。所以我必须定义它们的原始大小才能成功合并。我刚刚更新： drawing.DrawImage(globeVar.image1, 0, 0, globeVar.width1, globeVar.height1); drawing.DrawImage(globeVar.image2, (img.Width) / 2, 0, globeVar.width2, globeVar.height2); drawing.DrawImage(globeVar.image3, 0, (img.Height) / 2, globeVar.width3, globeVar.height3); drawing.DrawImage(globeVar.image4, (img.Width) / 2, (img.Height) / 2, globeVar.width4, globeVar.height4);从文档：我之前用过： DrawImage(Image, Int32, Int32)我现在使用： DrawImage(Image, Int32, Int32, Int32, Int32)