我正在使用地图(几个地图在嵌套的 json 中获取必要的元素)函数。我正在尝试根据所需的模板从 Neo4j 数据库中获取输出。在最后一张地图中,我正在构建所需输出的一部分,并将其存储在变量中:
px.segments.map(function(pathSegment){
individual_path.push({
"start": pathSegment.start.properties.name,
"weight": pathSegment.relationship.properties.Weight.low,
"end": pathSegment.end.properties.name});
})
然后我尝试:
console.log(individual_path);
我收到以下响应(因为其中一条记录在数据库中具有空值):
[ { start: 'A', weight: 0.6180339887498948, end: 'P2' } ]
[]
[ { start: 'P1', weight: 0.6180339887498948, end: 'A' },
{ start: 'A', weight: 0.6180339887498948, end: 'P2' } ]
[ { start: 'P1', weight: 0.6180339887498948, end: 'A' } ]
我的问题是,如何用非空替换空数组(在循环记录集时),如下所示:
[ { start: 'A', weight: 0.0, end: 'A' } ]
最后有类似的东西:
[ { start: 'A', weight: 0.6180339887498948, end: 'P2' } ]
*[ { start: 'A', weight: 0.0, end: 'A' } ]*
[ { start: 'P1', weight: 0.6180339887498948, end: 'A' },
{ start: 'A', weight: 0.6180339887498948, end: 'P2' } ]
[ { start: 'P1', weight: 0.6180339887498948, end: 'A' } ]
我不是很清楚,我会添加console.log(px); 输出:
Path {
start:
Node {
identity: Integer { low: 1, high: 0 },
labels: [ 'concept' ],
properties: { name: 'A', type: 'string' } },
end:
Node {
identity: Integer { low: 2, high: 0 },
labels: [ 'concept' ],
properties: { name: 'P2', type: 'string' } },
segments:
[ PathSegment { start: [Object], relationship: [Object], end: [Object] } ],
length: 1 }
Path {
start:
Node {
identity: Integer { low: 1, high: 0 },
labels: [ 'concept' ],
properties: { name: 'A', type: 'string' } },
end:
Node {
identity: Integer { low: 1, high: 0 },
labels: [ 'concept' ],
properties: { name: 'A', type: 'string' } },
segments: [],
length: 0 }
Path {
start:
Node {
identity: Integer { low: 0, high: 0 },
labels: [ 'concept' ],
properties: { name: 'P1', type: 'string' } },
end:
如您所见,其中一个块有一个空元素段,即第二个路径块。我需要的是能够用类型的对象替换空元素(开始:'',重量:,结束:'')
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