Python：分隔列表中的术语并赋值

Question

我使用了关键字提取器并获得了如下列表-

[('solutions design team', 0.5027793039863974), 

('communication skills', 0.039048703166463736), 

('internal stakeholders', 0.03230578820017667),

('potential customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]

我试图将这些单词中的每一个分开，并分别为每个单词分配相应的值（在右侧给出）。

例如-将“解决方案设计团队”= 0.5027793039863974 转换为

'solutions' = 0.5027793039863974, 

'design' = 0.5027793039863974 ,   

'team' = 0.5027793039863974.

Answer 1

如何使用双重平面理解重新创建一个带有分隔词的元组列表：inlist = [('solutions design team', 0.5027793039863974),('communication skills', 0.039048703166463736),('internal stakeholders', 0.03230578820017667),('potential customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]outlist = [(word,value) for words,value in inlist for word in words.split()]结果：>>> outlist[('solutions', 0.5027793039863974), ('design', 0.5027793039863974), ('team', 0.5027793039863974), ('communication', 0.039048703166463736), ('skills', 0.039048703166463736), ('internal', 0.03230578820017667), ('stakeholders', 0.03230578820017667), ('potential', 0.020380881551651655), ('customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]请注意，如果关键字出现多次，则元组列表中将出现重复项。如果你想累积它们，一个collections.defaultdict(float)对象可以很方便地创建一个带有关键字=>累积值的字典。accumulated = collections.defaultdict(float)for word,value in outlist:    accumulated[word] += value

Answer 2

字典理解，字典更新可以通过以下方式帮助您corpus = [('solutions design team', 0.5027793039863974), ('communication skills', 0.039048703166463736), ('internal stakeholders', 0.03230578820017667), ('potential customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]final_dict = {}for phase, prob in corpus:    final_dict.update({word:prob for word in phase.split()}print(final_dict['solutions'])print(final_dict['design'])