使用 1 个查询获取多个值

Question

+----+-----------+-----+

| ID | name      |price|

+----+-----------+-----+

|  1 |dest_tahiti|  10 |

|  2 |dest_bora  |  20 |

| ...|   ...     | ... | 

+----+-----------+-----+

      

$price="SELECT price FROM rates WHERE name IN('dest_tahiti','dest_bora', ...) ";

$price_prep= mysqli_query($connect,$price);

$price_result=  mysqli_fetch_array($price_prep);

echo $prix_result["price"] //Just display price for dest_tahiti with WHERE = 'dest_tahiti';

echo $prix_result["price"] //Just display price for dest_bora  with WHERE = 'dest_bora';

我想自定义的 值 WHERE name = ...进行相同的查询 与mysqli_fetch_array？你可以帮助我 ？

Answer 1

您可以在查询中包含名称作为输出。然后迭代返回的行并构建一个数组，其中索引是名称，值是价格。$price = "SELECT name, price FROM rates WHERE name IN('dest_tahiti','dest_bora', ...) ";$price_result = mysqli_query($connect, $price);$prix_result = [];while($row = mysqli_fetch_array($price_result, MYSQLI_ASSOC)) {  $prix_result[ $row['name'] ] = $row['price'];}echo $prix_result['dest_tahiti'];echo $prix_result['dest_bora'];