我在 Laravel 中有一个对象数组,我想对它们使用 where 查询,所以这里是我的代码:
array:18 [▼
0 => RoomPricingHistory {#498 ▼
#fillable: array:19 [▶]
#connection: "mysql"
#table: "room_pricing_histories"
#primaryKey: "id"
#keyType: "int"
+incrementing: true
#with: []
#withCount: []
#perPage: 15
+exists: true
+wasRecentlyCreated: false
#attributes: array:22 [▶]
#original: array:22 [▼
"id" => 326
"accommodation_room_id" => 1
"net_price" => null
"sales_price" => 3660000
"extra_bed_price" => null
"half_charge_price" => null
"half_board_price" => null
"full_board_price" => null
"foreign_net_price" => null
"foreign_sales_price" => null
"foreign_extra_bed_price" => null
"foreign_half_charge_price" => null
"foreign_half_board_price" => null
"foreign_full_board_price" => null
"operator_id" => 11
"commission_percent" => null
"discount_percent" => 5.0
"from_date" => "2019-05-25 09:00:00"
"to_date" => "2019-08-30 09:00:00"
"is_deleted" => 0
"created_at" => "2019-05-25 09:00:00"
"updated_at" => "2019-05-25 09:00:00"
]
#changes: []
#casts: []
#dates: []
#dateFormat: null
#appends: []
#dispatchesEvents: []
#observables: []
#relations: []
#touches: []
+timestamps: true
#hidden: []
#visible: []
#guarded: array:1 [▶]
}
所以现在在这里,例如我有 17 个房间,其中 5 个房间为 1,5 个房间的 id 为 2,7 个房间的 id 为 3 在这个结果中,我想获得每个房间的最后一个 sales_price 所以我最终会有 3 个结果与房间 id 1 -2 -3 和他们的最后价格。只是提一下我在结果之前按日期对它们进行了排序
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