Python字符串替换为字符并逐个字母递增

Question

目前我正在学习 python 脚本并试图获得以下输出

1BCD

2BCD

3BCD

11CD

21CD

31CD

12CD

22CD

32CD

13CD

23CD

33CD

111D

211D

311D

121D

221D

321D

等等......直到最后一个字符

如何实现？我正在使用 python 3.0，请在下面找到我的代码：

import sys

def tv():

    GET = 'ABCD'

    INC = 0

    IGKINNER = 0

    COUNT = 0

    i = 0

    while (COUNT < 1):

        IGKINNER = IGKINNER + 1

        try:

            for h in range(len(GET)):

                print('GET', GET)

                INC = INC + 1

                if (INC == 1):

                    GET = GET.replace(GET[IGKINNER], chr(49), 1)

                if (INC == 2):

                    GET = GET.replace(GET[IGKINNER], chr(50), 1)

                if (INC == 3):

                    GET = GET.replace(GET[IGKINNER], chr(51), 1)

                if (INC >=4):

                    INC = 0

                    break

        except:

            COUNT = 3

    return

tv()

请帮助我，非常感谢

Answer 1

您对所需内容的描述不是很清楚，但这会产生您想要的样子（GET每次都无需打印）：def tv():&nbsp; &nbsp; base = "ABCD"&nbsp; &nbsp; nums = "123"&nbsp; &nbsp; s4 = base[3]+nums&nbsp; &nbsp; s3 = base[2]+nums&nbsp; &nbsp; s2 = base[1]+nums&nbsp; &nbsp; for c4 in s4:&nbsp; &nbsp; &nbsp; &nbsp; for c3 in s3:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; for c2 in s2:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; for c1 in nums:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print(c1+c2+c3+c4)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; s2 = nums&nbsp; &nbsp; &nbsp; &nbsp; s3 = nums