前 1 个结果选择查询

Question

我收到以下错误

“错误编号：1064

您的 SQL 语法有错误；检查与您的 MySQL 服务器版本相对应的手册，了解在第 1 行的“1 Sum(picker_sign_out_sheet.lines_on_order) AS LINES, staff.staff_name AS PICKER”附近使用的正确语法

我不知道从哪里开始，希望得到一些帮助

("SELECT TOP 1 Sum(picker_sign_out_sheet.lines_on_order) AS LINES, staff.staff_name AS PICKER

FROM picker_sign_out_sheet INNER JOIN staff ON picker_sign_out_sheet.staff_name = staff.staff_id

WHERE (((picker_sign_out_sheet.finish_date)=Date()))

GROUP BY staff.staff_name

ORDER BY Sum(picker_sign_out_sheet.lines_on_order) DESC");

我期望得到 1 个结果，显示哪个用户的 lines_on_order 总和最高。

任何帮助都会很棒

Answer 1

请删除顶部 01 并获取所有并获取 $query->row_array();这仅返回一个顶部值

Answer 2

TOP 1 不是 MySQL 语法正确的查询是SELECT Sum(picker_sign_out_sheet.lines_on_order) AS LINES, staff.staff_name AS PICKERFROM picker_sign_out_sheet INNER JOIN staff ON picker_sign_out_sheet.staff_name = staff.staff_idWHERE (((picker_sign_out_sheet.finish_date)=Date()))GROUP BY staff.staff_nameORDER BY Sum(picker_sign_out_sheet.lines_on_order) DESCLIMIT 1