我在这里有一个登录页面,其中有两个字段和一个提交按钮。代码看起来不错,但是当我按下提交按钮时,没有任何内容传递给 isset 方法。这是我的代码。
<?php
function security($database,$value)
{
$new_val=stripslashes($value);
$new_val=mysqli_real_escape_string($database,$value);
return $new_val;
}
require_once("database.php");
if(isset($_POST['submit']))
{
echo "working";
$username=security("betit",$_POST['username']);
$paassword=security("betit",$_POST['password']);
$sql="SELECT * FROM user_info WHERE username='$username' and password='$password'";
$result=mysqli_query("betit",$sql);
if($result)
{
echo "congrats";
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title>LOGIN</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.4.0/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.0/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.4.0/js/bootstrap.min.js"></script>
</head>
<body>
<div class="container">
<div class="row">
<h3>Login</h3>
<div class="col-3">
<form method="post" action="" >
<div class="input-group">
<span class="input-group-addon"><i class="glyphicon glyphicon-user"></i></span>
<input id="email" type="text" class="form-control" name="username" placeholder="Username">
</div>
<div class="input-group">
<span class="input-group-addon"><i class="glyphicon glyphicon-lock"></i></span>
<input id="password" type="password" class="form-control" name="password" placeholder="Password">
</div>
<input type="button" class="btn btn-primary" name="submit" value="submit">
</form>
</div>
</div>
</div>
</body>
</html>
数据库.php
<?php
function db_connection($hostname, $username, $password, $database)
{
$link = mysqli_connect($hostname, $username, $password, $database);
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
提交按钮应该调用 isset 方法,但没有通过。我只是无法确定它是什么类型的错误。
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