转到：数组数组，切片数组，数组切片和切片切片

Question

试图自学，发现很难找到例子，我的大脑已经陷入困境。非常不确定3和4，需要帮助使5正常工作。

package main

import "fmt"

func main () {

    println("0. Array:")

    var a = [...]int{4,5,6,7,8,9} //assign

    fmt.Println(a,"\n")

    println("1. Slice:")

    var as []int

    as = a[:] //assign

    fmt.Println(as,"\n")

    println("2. Array of arrays:")

    var b [4][len(a)]int

    for i:= range b { //assign

        b[i]=a

    }

    fmt.Println(b,"\n")

    println("3. Array of slices:")

    var d [len(b)][]int

    for i:= range b { // assign

        d[i] = b[i][:] //does this really work?

    }

    fmt.Println(d,"\n")

    println("4. Slice of arrays:")

    var c [][len(a)]int

    c = b[:][:] // assign, does this really work?

    fmt.Println(c,"\n")

    println("5. Slice of slices:")

    var e [][]int

//  e = c //  ???

    fmt.Println(e,"\n")

}

Answer 1

答案是“这真的有用吗？” 取决于您的期望。在http://play.golang.org/p/7Z5hKioTI_中考虑此示例package mainimport "fmt"func main() {    fmt.Println("0. Array:")    var a = [...]int{4, 5, 6, 7, 8, 9}  //assign    fmt.Println(a, "\n")    fmt.Println("1. Slice:")    var as []int    as = a[:]   //assign    fmt.Println(as, "\n")    fmt.Println("new slice:")    ns := make([]int, len(a))    copy(ns, a[:])    fmt.Print(ns, "\n\n")    fmt.Println("modifying array...")    a[0] = 10    fmt.Print("array is now:\n", a, "\n\n")    fmt.Print("slice is now:\n", as, "\n\n")    fmt.Print("new slice is still:\n", ns, "\n")}它显示了切片如何具有基础数组，以及OP中的示例使用相同的基础数组来构成切片。如果要使切片具有独立的内容，则必须制作新的切片并复制数据。（或者有附加的技巧...）另外请注意，println将数据发送到stderr而不是stdout，并且将某些数据类型的格式设置为与fmt.Println不同。为避免混淆，最好保持使用fmt.Println的习惯。