如何将单词从对象打印到javascript中的指定位置

Question

我在javascript中有对象，对象的键是我的段落中的单词，如何在段落中打印它.Value（key：value）保持其位置。

尝试使用for循环获取对我不起作用

var userdata= {

          "\"Ten": [

            0

          ],

          "blue": [

            1

          ],

          "links\"": [

            2

          ],

          "have": [

            3

          ],

          "defined": [

            4

          ],

          "web": [

            5,

            36,

            65

          ],

          "search": [

            6,

            32,

            37,

            70,

            90,

            108,

            126

          ],

          "results": [

            7,

            33,

            38,

            71,

            82,

            99,

            119

          ],

          "for": [

            8,

            80

          ],

          "the": [

            9,

            28,

            56,

            61,

            69,

            95,

            105

          ],

          "last": [

            10

          ],

          "fifteen": [

            11

          ],

          "years": [

            12

          ],

          "--": [

            13

          ],

          "snippets": [

            14

          ],

          "of": [

            15,

            30,

            63,

            97,

            107,

            125

          ],

        };

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Answer 1

使用将对象转换为单词/索引对Object.entries()。使用迭代条目Array.reduce()。在reduce中，用迭代索引Array.forEach()，并将每个单词分配给累加器（r）中的索引。用空格将单词数组连接起来。const userdata = {"\"Ten":[0],"blue":[1],"links\"":[2],"have":[3],"defined":[4],"web":[5,36,65],"search":[6,32,37,70,90,108,126],"results":[7,33,38,71,82,99,119],"for":[8,80],"the":[9,28,56,61,69,95,105],"last":[10],"fifteen":[11],"years":[12],"--":[13],"snippets":[14],"of":[15,30,63,97,107,125],"text":[16],"combined":[17],"with":[18,60],"document":[19],"titles":[20],"and":[21,46,52,85],"URLs.":[22],"In":[23],"this":[24],"paper,":[25],"we":[26,111,114],"establish":[27],"notion":[29],"enhanced":[31,81,98,118],"that":[34,54,75,113],"extend":[35],"to":[39,58,103,120],"include":[40],"multimedia":[41],"objects":[42],"such":[43],"as":[44],"images":[45],"video,":[47],"intent-specific":[48],"key":[49],"value":[50],"pairs,":[51],"elements":[53],"allow":[55],"user":[57],"interact":[59],"contents":[62],"a":[64,78,122],"page":[66],"directly":[67],"from":[68],"page.":[72],"We":[73,92],"show":[74,112],"users":[76,102],"express":[77],"preference":[79],"both":[83],"explicitly,":[84],"when":[86],"observed":[87],"in":[88,100],"their":[89],"behavior.":[91],"also":[93],"demonstrate":[94],"effectiveness":[96],"helping":[101],"assess":[104],"relevance":[106],"results.":[109],"Lastly,":[110],"can":[115],"efficiently":[116],"generate":[117],"cover":[121],"significant":[123],"fraction":[124],"result":[127],"pages.":[128]};const result = Object.entries(userdata)  .reduce((r, [word, indexes]) => {    indexes.forEach(index => r[index] = word);        return r;  }, [])  .join(' ');  console.log(result);

Answer 2

您可以遍历该对象，然后取得金钥名称（word）使用以下位置提供的位置（index）userdata[word]在结果数组中定义要使用的索引和单词，例如arrResult[index] = word。然后，使用' '定界符将该数组连接到字符串中例如：var userdata = {"\"Ten":[0],"blue":[1],"links\"":[2],"have":[3],"defined":[4],"web":[5,36,65],"search":[6,32,37,70,90,108,126],"results":[7,33,38,71,82,99,119],"for":[8,80],"the":[9,28,56,61,69,95,105],"last":[10],"fifteen":[11],"years":[12],"--":[13],"snippets":[14],"of":[15,30,63,97,107,125],"text":[16],"combined":[17],"with":[18,60],"document":[19],"titles":[20],"and":[21,46,52,85],"URLs.":[22],"In":[23],"this":[24],"paper,":[25],"we":[26,111,114],"establish":[27],"notion":[29],"enhanced":[31,81,98,118],"that":[34,54,75,113],"extend":[35],"to":[39,58,103,120],"include":[40],"multimedia":[41],"objects":[42],"such":[43],"as":[44],"images":[45],"video,":[47],"intent-specific":[48],"key":[49],"value":[50],"pairs,":[51],"elements":[53],"allow":[55],"user":[57],"interact":[59],"contents":[62],"a":[64,78,122],"page":[66],"directly":[67],"from":[68],"page.":[72],"We":[73,92],"show":[74,112],"users":[76,102],"express":[77],"preference":[79],"both":[83],"explicitly,":[84],"when":[86],"observed":[87],"in":[88,100],"their":[89],"behavior.":[91],"also":[93],"demonstrate":[94],"effectiveness":[96],"helping":[101],"assess":[104],"relevance":[106],"results.":[109],"Lastly,":[110],"can":[115],"efficiently":[116],"generate":[117],"cover":[121],"significant":[123],"fraction":[124],"result":[127],"pages.":[128]};let arrResult = [];for (let word in userdata){  userdata[word].forEach((i) =>  {    arrResult[i] = word;  });}let result = arrResult.join(' ');console.log(result);