根据URL动态路由到Flask操作

Question

想要一个快速且肮脏的Flask测试服务器，可以在其中输入网址路径

0.0.0.0/**something**

并使其调用具有相同名称的相应方法。

像这样的东西：

from flask import Flask

app = Flask(__name__)

@app.route('/<action>')

def do_it(action=None):

    if {PSEUDO: The method exists, call it}

    else:

        return 'Action not found'

def something():

    return 'Did something'

if __name__ == '__main__':

    app.run()

Flask是否有帮助解决此问题的机制，还是我必须对反射感到混乱？

Answer 1

不知道那有多凌乱，但似乎很简单：&nbsp; try:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;&nbsp; &nbsp; &nbsp; return globals()[action]()&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;&nbsp; except KeyError:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; &nbsp; &nbsp; return 'Action not found'&nbsp;