打印的行在Python中表现奇怪

Question

我正试图在几个循环中打印出一行的行，并且我想找到一种打印行而不用的方法\n，因为在每个循环完成后都会添加一个空行。我拥有的代码示例如下：

def compose_line6(self, pointers, pointers_synset_type):    

    self.line6 = ''

    for A, B in zip(pointers, pointers_synset_type):

        self.line6 += 'http://www.example.org/lexicon#'+A+' http://www.monnetproject.eu/lemon#pos '+B+'\n'

    return self.line6

def compose_line7(self, pointers, pointer_source_target):

    self.line7 = ''

    for A, B in zip(pointers, pointer_source_target):

        self.line7 += 'http://www.example.org/lexicon#'+A+' http://www.monnetproject.eu/lemon#source_target '+B+'\n'

    return self.line7

def compose_contents(self, line1, line2, line3, line4, line5, line6, line7):

    self.contents = '''\

    '''+line1+'''

    '''+line2+'''

    '''+line3+'''

    '''+line4+'''

    '''+line5+'''

    '''+line6+'''

    '''+line7+''''''

    return self.contents

def print_lines(self, contents):

    print (contents)

当我打印这些时，会发生以下情况：

        http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#pos n

http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#pos a

http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#pos v

http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#pos v

http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#pos v

我想要这样：

http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#pos n

http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#pos a

http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#pos v

http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#pos v

http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#pos v    

Answer 1

您需要先关闭引号，然后再添加换行符：'''\    '''+line1+'''    '''+line2+'''    '''+line3+'''    '''+line4+'''    '''+line5+'''    '''+line6+'''    '''+line7+''''''您逃脱了第一行换行符，但仍在后面添加了4个空格line1。尝试这个：print("\n".join([line1, line2, line3, line4, line5, line 6, line7]))

Answer 2

采用：def compose_contents(self, line1, line2, line3, line4, line5, line6, line7):    self.contents = '\n'.join([line1, line2, line3, line4, line5, line6, line7])    return self.contents和：print contents,注意最后的逗号！

Answer 3

在Python 2.x中，它将是print "Text",-逗号后不包含任何内容。在Python 3.x中，它将是print("Text", end="")-print()函数的特殊参数。