正则表达式在python中嵌套括号

Question

我有这样的事情：

Othername California (2000) (T) (S) (ok) {state (#2.1)}

是否有正则表达式代码可获取：

Othername California ok 2.1

也就是说，我想将数字保持在圆括号内，将其依次放在{}内，并将文本“ ok”保持在（）内。我特别需要打印出“ ok”字符串（如果包含在我的行中），但是我想去除括号内的其他文本，例如（V），（S）或（2002）。

我知道，正则表达式可能不是解决此类问题的最有效方法。

任何帮助，将不胜感激。

编辑：

该字符串可能会有所不同，因为该行中不包含如果某些信息不可用。文本本身也是可变的（例如，我没有每一行都有“状态”）。因此，可以有例如：

Name1 Name2 Name3 (2000) (ok) {edu (#1.1)}

Name1 Name2 (2002) {edu (#1.1)}

Name1 Name2 Name3 (2000) (V) {variation (#4.12)}

Answer 1

尽管我在评论中说了什么。我找到了一种解决方法：(?(?=\([^()\w]*[\w.]+[^()\w]*\))\([^()\w]*([\w.]+)[^()\w]*\)|.)(?=[^{]*\})|(?<!\()(\b\w+\b)(?!\()|ok解释：(?&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; # If(?=\([^()\w]*[\w.]+[^()\w]*\))&nbsp; &nbsp; &nbsp; # There is (anything except [()\w] zero or more times, followed by [\w.] one or more times, followed by anything except [()\w] zero or more times)\([^()\w]*([\w.]+)[^()\w]*\)&nbsp; &nbsp; &nbsp; &nbsp; # Then match it, and put [\w.] in a group|&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;# else.&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;# advance with one character)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;# End if(?=[^{]*\})&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;# Look ahead if there is anything except { zero or more times followed by }|&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;# Or(?<!\()(\b\w+\b)(?!\()&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; # Match a word not enclosed between parenthesis|&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;# Orok&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; # Match ok