从tweepy异常实例获取错误代码

Question

我是python的新手，正在尝试使用一个库。它提出了一个例外，我正在尝试确定哪个例外。这是我正在尝试的：

except tweepy.TweepError as e:

    print e

    print type(e)

    print e.__dict__

    print e.reason

    print type(e.reason)

这就是我得到的：

[{u'message': u'Sorry, that page does not exist', u'code': 34}]

<class 'tweepy.error.TweepError'>

{'reason': u"[{u'message': u'Sorry, that page does not exist', u'code': 34}]", 'response': <httplib.HTTPResponse instance at 0x00000000029CEAC8>}

[{u'message': u'Sorry, that page does not exist', u'code': 34}]

<type 'unicode'>

我正在尝试获取该代码。我尝试了e.reason.code，但没有成功，我也不知道要尝试什么。

Answer 1

这个怎么样？except tweepy.TweepError as e:&nbsp; &nbsp; print e.message[0]['code']&nbsp; # prints 34&nbsp; &nbsp; print e.args[0][0]['code']&nbsp; # prints 34

Answer 2

要仅获取错误代码，请使用发布的monq方法。以下示例说明了如何同时获取错误代码和消息。我必须从e.reason字符串中提取消息，如果有人有更好的方法来仅检索消息，请分享。注意：此代码应适用于以下格式的任何错误代码/原因。[{'code'：50，'message'：'找不到用户。'}]def getExceptionMessage(msg):&nbsp; &nbsp; words = msg.split(' ')&nbsp; &nbsp; errorMsg = ""&nbsp; &nbsp; for index, word in enumerate(words):&nbsp; &nbsp; &nbsp; &nbsp; if index not in [0,1,2]:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; errorMsg = errorMsg + ' ' + word&nbsp; &nbsp; errorMsg = errorMsg.rstrip("\'}]")&nbsp; &nbsp; errorMsg = errorMsg.lstrip(" \'")&nbsp; &nbsp; return errorMsg您可以这样称呼它：try:&nbsp; &nbsp; # Some tweepy api call, ex) api.get_user(screen_name = usrScreenName)except tweepy.TweepError as e:&nbsp; &nbsp; print (e.api_code)&nbsp; &nbsp; print (getExceptionMessage(e.reason))