手动替换列表中的元素

Question

例子：

a = [1,2,3,2,4,2,5]

for key in a:

    if key == 2:

        key = 10

print key

结果： [1,10,3,10,4,10,5]

我需要Python手动“询问”要替换的元素。

Answer 1

>>> a = [1,2,3,2,4,2,5]>>> a[:] = [10 if x==2 else x for x in a]>>> a[1, 10, 3, 10, 4, 10, 5]如果要替换多个项目，请考虑使用dict：>>> dic = {2 : 10}>>> a[:] = [dic.get(x,x) for x in a]>>> a[1, 10, 3, 10, 4, 10, 5]

Answer 2

您正在寻找enumerate()：for indx, ele in enumerate(a):    if ele == 2:        a[indx] = 10print a印刷：[1, 10, 3, 10, 4, 10, 5]如果要更改的值是输入，则只需执行以下操作：change = map(int, raw_input("What number do you want to change in the list? And what number should it be? Separate both numbers with a space ").split())for indx, _ in enumerate(a):    if change[0] == 2:        a[indx] = change[1]或作为列表理解（如果您喜欢此解决方案，请支持Ashwini的:)）：change = map(int, raw_input("What number do you want to change in the list? And what number should it be? Separate both numbers with a space ").split())[change[1] if x == change[0] else x for x in a]