哪一种是使用熊猫处理实时传入数据的最推荐/ Python方法?
每隔几秒钟,我就会收到以下格式的数据点:
{'time' :'2013-01-01 00:00:00', 'stock' : 'BLAH',
'high' : 4.0, 'low' : 3.0, 'open' : 2.0, 'close' : 1.0}
我想将其附加到现有的DataFrame上,然后对其进行一些分析。
问题是,仅将DataFrame.append添加到行中可能会导致所有复制的性能问题。
我尝试过的事情:
一些人建议预分配一个大的DataFrame并在数据输入时对其进行更新:
In [1]: index = pd.DatetimeIndex(start='2013-01-01 00:00:00', freq='S', periods=5)
In [2]: columns = ['high', 'low', 'open', 'close']
In [3]: df = pd.DataFrame(index=t, columns=columns)
In [4]: df
Out[4]:
high low open close
2013-01-01 00:00:00 NaN NaN NaN NaN
2013-01-01 00:00:01 NaN NaN NaN NaN
2013-01-01 00:00:02 NaN NaN NaN NaN
2013-01-01 00:00:03 NaN NaN NaN NaN
2013-01-01 00:00:04 NaN NaN NaN NaN
In [5]: data = {'time' :'2013-01-01 00:00:02', 'stock' : 'BLAH', 'high' : 4.0, 'low' : 3.0, 'open' : 2.0, 'close' : 1.0}
In [6]: data_ = pd.Series(data)
In [7]: df.loc[data['time']] = data_
In [8]: df
Out[8]:
high low open close
2013-01-01 00:00:00 NaN NaN NaN NaN
2013-01-01 00:00:01 NaN NaN NaN NaN
2013-01-01 00:00:02 4 3 2 1
2013-01-01 00:00:03 NaN NaN NaN NaN
2013-01-01 00:00:04 NaN NaN NaN NaN
另一种选择是建立字典列表。只需将传入的数据附加到列表中,然后将其切成较小的DataFrame,即可完成工作。
In [9]: ls = []
In [10]: for n in range(5):
.....: # Naive stuff ahead =)
.....: time = '2013-01-01 00:00:0' + str(n)
.....: d = {'time' : time, 'stock' : 'BLAH', 'high' : np.random.rand()*10, 'low' : np.random.rand()*10, 'open' : np.random.rand()*10, 'close' : np.random.rand()*10}
.....: ls.append(d)
In [11]: df = pd.DataFrame(ls[1:3]).set_index('time')
In [12]: df
Out[12]:
close high low open stock
time
2013-01-01 00:00:01 3.270078 1.008289 7.486118 2.180683 BLAH
2013-01-01 00:00:02 3.883586 2.215645 0.051799 2.310823 BLAH
或类似的东西,也许要多处理一些输入。
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