在双监视器配置中的特定屏幕上显示JFrame

Question

我有一个双监视器配置，如果找到它，我想在特定的监视器中运行我的GUI。我试图创建JFrame一个通过GraphicConfiguration屏幕设备对象的窗口，但是它不起作用，框架仍显示在主屏幕上。

如何设置必须显示框架的屏幕？

Answer 1

public static void showOnScreen( int screen, JFrame frame ){&nbsp; &nbsp; GraphicsEnvironment ge = GraphicsEnvironment&nbsp; &nbsp; &nbsp; &nbsp; .getLocalGraphicsEnvironment();&nbsp; &nbsp; GraphicsDevice[] gs = ge.getScreenDevices();&nbsp; &nbsp; if( screen > -1 && screen < gs.length )&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; gs[screen].setFullScreenWindow( frame );&nbsp; &nbsp; }&nbsp; &nbsp; else if( gs.length > 0 )&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; gs[0].setFullScreenWindow( frame );&nbsp; &nbsp; }&nbsp; &nbsp; else&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; throw new RuntimeException( "No Screens Found" );&nbsp; &nbsp; }}

Answer 2

以允许在不强制全屏的情况下实现此目的：public static void showOnScreen( int screen, JFrame frame ) {    GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();    GraphicsDevice[] gd = ge.getScreenDevices();    if( screen > -1 && screen < gd.length ) {        frame.setLocation(gd[screen].getDefaultConfiguration().getBounds().x, frame.getY());    } else if( gd.length > 0 ) {        frame.setLocation(gd[0].getDefaultConfiguration().getBounds().x, frame.getY());    } else {        throw new RuntimeException( "No Screens Found" );    }}在这段代码中，我假设getDefaultConfiguration()永远不会返回null。如果不是这种情况，请有人纠正我。但是，此代码可将您JFrame移至所需的屏幕。

Answer 3

阅读屏幕2上有关JFrame.setLocationRelativeTo的文档后，一种更清洁的解决方案public void moveToScreen() {&nbsp; &nbsp; setVisible(false);&nbsp; &nbsp; GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();&nbsp; &nbsp; GraphicsDevice[] screens = ge.getScreenDevices();&nbsp; &nbsp; int n = screens.length;&nbsp; &nbsp; for (int i = 0; i < n; i++) {&nbsp; &nbsp; &nbsp; &nbsp; if (screens[i].getIDstring().contentEquals(settings.getScreen())) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; JFrame dummy = new JFrame(screens[i].getDefaultConfiguration());&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; setLocationRelativeTo(dummy);&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; dummy.dispose();&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }&nbsp; &nbsp; setVisible(true);}此功能可用于在屏幕之间切换应用程序窗口