UITapGestureRecognizer-单击和双击

Question

我正在尝试向UITapGestureRecognizers视图添加2 ，一个用于单击，一个用于双击事件。单抽头识别器正在按预期运行（单独运行）。但是我似乎无法使双击识别器正常工作。

已经尝试具有类似性质的实验：cancelsTouchesInView，delaysTouchesBegan和delaysTouchesEnded，但仍然无法正常工作。

当我双击时，将始终激活单击识别器，并且还将将双击事件发送到超级视图。但是自定义双击识别器似乎根本没有得到通知。

文档似乎表明可以将上述3个属性用于此目的。但是我不确定应该设置哪些值以及在哪些识别器上（单，双或双）。希望有人对此有所帮助。

以下是最新更新的代码块。

// ****** gesture recognizers ******

- (void)addSingleAndDoubleTapGestureRecognizersToView:(UIView *)view

{

    // single tap    

    UITapGestureRecognizer *singleTapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget: tableViewController action: @selector(handleSingleTapOnView:)];                                 

    [singleTapRecognizer setNumberOfTouchesRequired:1];

    [view addGestureRecognizer: singleTapRecognizer];

    // double tap 

    UITapGestureRecognizer *doubleTapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget: tableViewController action: @selector (handleDoubleTapOnView:)];        

    [doubleTapRecognizer setNumberOfTouchesRequired:2];         

    [singleTapRecognizer requireGestureRecognizerToFail: doubleTapRecognizer];

    [view addGestureRecognizer: doubleTapRecognizer];         

}

- (void)handleSingleTapOnView:(id)sender

{

}

- (void)handleDoubleTapOnView:(id)sender

{

}

Answer 1

UITapGestureRecognizer *singleTap = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doSingleTap)] autorelease];singleTap.numberOfTapsRequired = 1; [self.view addGestureRecognizer:singleTap];UITapGestureRecognizer *doubleTap = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doDoubleTap)] autorelease];doubleTap.numberOfTapsRequired = 2; [self.view addGestureRecognizer:doubleTap];[singleTap requireGestureRecognizerToFail:doubleTap];注意： 如果要使用 numberOfTouchesRequired 它，必须 .numberOfTouchesRequired = 1;对于斯威夫特let singleTapGesture = UITapGestureRecognizer(target: self, action: #selector(didPressPartButton))singleTapGesture.numberOfTapsRequired = 1view.addGestureRecognizer(singleTapGesture)let doubleTapGesture = UITapGestureRecognizer(target: self, action: #selector(didDoubleTap))doubleTapGesture.numberOfTapsRequired = 2view.addGestureRecognizer(doubleTapGesture)singleTapGesture.require(toFail: doubleTapGesture)

Answer 2

Swift 3解决方案：let singleTap = UITapGestureRecognizer(target: self, action:#selector(self.singleTapAction(_:)))singleTap.numberOfTapsRequired = 1view.addGestureRecognizer(singleTap)let doubleTap = UITapGestureRecognizer(target: self, action:#selector(self.doubleTapAction(_:)))doubleTap.numberOfTapsRequired = 2view.addGestureRecognizer(doubleTap)singleTap.require(toFail: doubleTap)在代码行singleTap.require（toFail：doubleTap）中，我们强制单击以等待并确保tap事件不是双击。

Answer 3

// ----首先，您必须分配双击手势------- //UITapGestureRecognizer* doubleTap = [[UITapGestureRecognizer alloc] initWithTarget : self action : @selector (handleDoubleTap:)];UITapGestureRecognizer* singleTap = [[UITapGestureRecognizer alloc] initWithTarget : self action : @selector (handleSingleTap:)];[singleTap requireGestureRecognizerToFail : doubleTap];[doubleTap setDelaysTouchesBegan : YES];[singleTap setDelaysTouchesBegan : YES];// -----------------------抽头数---------------- //[doubleTap setNumberOfTapsRequired : 2];[singleTap setNumberOfTapsRequired : 1];// -------在视图或按钮上添加双击和单击手势-------- //[self.view addGestureRecognizer : doubleTap];[self.view addGestureRecognizer : singleTap];