Gson处理对象或数组
我有以下课程
public class MyClass {
private List<MyOtherClass> others;
}
public class MyOtherClass {
private String name;
}
我有可能看起来像这样的JSON
{
others: {
name: "val"
}
}
或这个
{
others: [
{
name: "val"
},
{
name: "val"
}
]
}
我希望能够MyClass对这两种JSON格式使用相同的格式。有办法用Gson做到这一点吗？
潇湘沐浏览 773回答 3
3回答
-
慕沐林林
谢谢您提供的三个杯子！如果需要多个类型，则与泛型类型相同：public class SingleElementToListDeserializer<T> implements JsonDeserializer<List<T>> {private final Class<T> clazz;public SingleElementToListDeserializer(Class<T> clazz) { this.clazz = clazz;}public List<T> deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException { List<T> resultList = new ArrayList<>(); if (json.isJsonArray()) { for (JsonElement e : json.getAsJsonArray()) { resultList.add(context.<T>deserialize(e, clazz)); } } else if (json.isJsonObject()) { resultList.add(context.<T>deserialize(json, clazz)); } else { throw new RuntimeException("Unexpected JSON type: " + json.getClass()); } return resultList; }}并配置Gson：Type myOtherClassListType = new TypeToken<List<MyOtherClass>>() {}.getType();SingleElementToListDeserializer<MyOtherClass> adapter = new SingleElementToListDeserializer<>(MyOtherClass.class);Gson gson = new GsonBuilder() .registerTypeAdapter(myOtherClassListType, adapter) .create(); -
波斯汪
建立三杯的答案，我有以下让JsonArray直接反序列化为数组的方法。static public <T> T[] fromJsonAsArray(Gson gson, JsonElement json, Class<T> tClass, Class<T[]> tArrClass) throws JsonParseException { T[] arr; if(json.isJsonObject()){ //noinspection unchecked arr = (T[]) Array.newInstance(tClass, 1); arr[0] = gson.fromJson(json, tClass); }else if(json.isJsonArray()){ arr = gson.fromJson(json, tArrClass); }else{ throw new RuntimeException("Unexpected JSON type: " + json.getClass()); } return arr;}用法： String response = "......."; JsonParser p = new JsonParser(); JsonElement json = p.parse(response); Gson gson = new Gson(); MyQuote[] quotes = GsonUtils.fromJsonAsArray(gson, json, MyQuote.class, MyQuote[].class);
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